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kolbaska11 [484]
3 years ago
10

As a reward for winning a math competition, 26 students in the 7th grade visited a theme park. On one ride, 3 equal groups of st

udents could be seated and 2 students were left over. Write and solve an equation to find how many students could be seated in each group.
Mathematics
1 answer:
seraphim [82]3 years ago
8 0

Answer: in each group, there are 8 students.

Step-by-step explanation:

We have a total of 26 students.

If we separate them into 3 equal groups (suppose that each group has X students) and leave 2 students left, we will have the relation:

3*X + 2 = 26

This means that 3 times the number of students in each group, plus the two students leftover must be equal to the initial number of students.

Now we can solve this for X.

3*X + 2 = 26

3*X = 26 - 2 = 24

X = 24/3 = 8

X = 8

This means that in each group there are 8 students.

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the area of a parallelogram shape land is on the square and length of its two adjacent sides are 25 m and 17 M find its diagonal
Alex787 [66]

Step-by-step explanation:

Draw diagonal AC

The triangle ABC has sides 17 and 25

Say AB is 17, BC is 25

Draw altitude on side BC from A , say h

h = 17 sin B

Area = 25*17 sin B = 408

sin B = 24/25

In ∆ ABC

Cos B = +- 7/25

= 625 + 289 — b^2 / 2*25*17

b^2 = 914 — 14*17 = 676

b = 26

h = 17*24/25 = 408/25 = 16.32

Draw the second diagonal BD

In ∆ BCD, draw altitude from D, say DE =h

BD^2 = h^2 + {(25 + sqrt (289 -h^2) }^2

BD^2 = 16.32^2 + (25 + 4.76)^2

= 885.6576 + 266.3424

BD = √ 1152 = 33.94 m

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3 years ago
PLEASE HELP!!
ruslelena [56]

Answer: 104 miles

Step-by-step explanation:

If 2.5 in = 52 mi, and 2.5 × 2 = 5, then 2.5(2) = 52(2)

5 in = 104 mi

3 0
3 years ago
Expand ( 2 − x ) 5 and identify each part of the expression.
dimaraw [331]
You use distributive property. So (5 x 2)-(5 x x)= 10 - 5x.
8 0
4 years ago
A snack bar sells popcorn in cone-shaped containers. one container has a diameter of 8 inches and a height of 10 inches. how man
uysha [10]
We know that the volume of a cone is given by the following relation:  
V = (pi * r^2 * h)/3 
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What must the radius of C be for PR to be tangent to it at Q?
Setler79 [48]

Answer:

D. 8

Step-by-step explanation:

Draw segment CQ which will be perpendicular to tangent PR.

So, triangle CQR will be right angled triangle right angle at Q.

Let radius of the circle be r.

Therefore,

CQ = CS = r

By Pythagoras Theorem:

{(r + 9)}^{2}  =  {r}^{2}  +  {15}^{2}  \\  \\  {r}^{2}  + 18r + 81 =  {r}^{2}  + 225 \\  \\ 18r = 225 - 81 \\  \\ 18r = 144 \\  \\ r =  \frac{144}{18}  \\  \\ r = 8

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