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kolbaska11 [484]
3 years ago
10

As a reward for winning a math competition, 26 students in the 7th grade visited a theme park. On one ride, 3 equal groups of st

udents could be seated and 2 students were left over. Write and solve an equation to find how many students could be seated in each group.
Mathematics
1 answer:
seraphim [82]3 years ago
8 0

Answer: in each group, there are 8 students.

Step-by-step explanation:

We have a total of 26 students.

If we separate them into 3 equal groups (suppose that each group has X students) and leave 2 students left, we will have the relation:

3*X + 2 = 26

This means that 3 times the number of students in each group, plus the two students leftover must be equal to the initial number of students.

Now we can solve this for X.

3*X + 2 = 26

3*X = 26 - 2 = 24

X = 24/3 = 8

X = 8

This means that in each group there are 8 students.

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X + 6 - 3 = 4x + 8<br> solve for x
Mademuasel [1]

Answer:

x= -3/5

Step-by-step explanation:

x+3=4x+8

-8      -x

-5 = 3x

-5/3 = x

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Simplify the radical
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Answer:

-3 sqrt 11

Step-by-step explanation:

The sqrt is the same so you just muliply the outside numbers normally.

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3 years ago
Simplify the function f(x)=1/3(81)^3x/4 . Then determine the key aspects of the function. The initial value is . The simplified
BartSMP [9]
<span><span> x3-81=0</span> </span>One solution was found :                  <span> x = 3 • ∛<span>3 </span>= 4.3267</span>

Step by step solution :<span>Step  1  :</span>Trying to factor as a Difference of Cubes:

<span> 1.1 </span>     Factoring: <span> x3-81</span> 

Theory : A difference of two perfect cubes, <span> <span>a3</span> - <span>b3</span> </span>can be factored into
            <span>  (a-b) • (a2 +ab +b2)</span>

Proof : <span> (a-b)•(a2+ab+b2) =
            <span>a3</span>+<span>a2b</span>+<span>ab2</span>-<span>ba2</span>-<span>b2a</span>-<span>b3</span> =
            <span>a3</span>+(<span>a2b</span>-<span>ba2</span>)+(<span>ab2</span>-<span>b2a</span>)-<span>b3</span> =
            <span>a3</span>+0+0+<span>b3</span> =
            <span>a3</span>+<span>b3</span></span>

<span>Check :  81  is not a cube !! </span>
Ruling : Binomial can not be factored as the difference of two perfect cubes

Polynomial Roots Calculator :

<span> 1.2 </span>   Find roots (zeroes) of :      <span> F(x) = x3-81</span>
Polynomial Roots Calculator is a set of methods aimed at finding values of  x  for which   F(x)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  x  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q  then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  1  and the Trailing Constant is <span> -81. 

 </span>The factor(s) are: 

of the Leading Coefficient : <span> 1
 </span>of the Trailing Constant : <span> 1 ,3 ,9 ,27 ,81 

 </span>Let us test ....

<span><span>  P  Q  P/Q  F(P/Q)   Divisor</span><span>     -1     1      -1.00      -82.00   </span><span>     -3     1      -3.00      -108.00   </span><span>     -9     1      -9.00      -810.00   </span><span>     -27     1     -27.00     -19764.00   </span><span>     -81     1     -81.00     -531522.00   </span><span>     1     1      1.00      -80.00   </span><span>     3     1      3.00      -54.00   </span><span>     9     1      9.00      648.00   </span><span>     27     1      27.00     19602.00   </span><span>     81     1      81.00     531360.00   </span></span>


Polynomial Roots Calculator found no rational roots

<span>Equation at the end of step  1  :</span><span> x3 - 81 = 0 </span><span>Step  2  :</span>Solving a Single Variable Equation :

<span> 2.1 </span>     Solve  :   <span> x3-81 = 0</span><span> 

 </span>Add  81  to both sides of the equation :<span> 
 </span>                    <span> x3 = 81</span> 
When two things are equal, their cube roots are equal. Taking the cube root of the two sides of the equation we get: <span> 
 </span>                     x  = <span> ∛<span> 81 </span></span><span> 

 </span>Can <span> ∛<span> 81 </span></span>be simplified ?

Yes!   The prime factorization of  81   is
  <span> 3•3•3•3</span>  
To be able to remove something from under the radical, there have to be <span> 3 </span> instances of it (because we are taking a cube i.e.<span> cube </span>root).

<span>∛<span> 81 </span>  =  ∛<span> 3•3•3•3 </span>  =
                <span>3 </span>• ∛<span> 3 </span></span>

The equation has one real solution
This solution is <span> x = 3 • ∛<span>3 </span>= 4.3267 </span>

One solution was found :                  <span> x = 3 • ∛<span>3 </span>= 4.3267</span>
7 0
4 years ago
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Lilit [14]

Answer:

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Step-by-step explanation:

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