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hichkok12 [17]
3 years ago
5

Help it’s due tomorrow

Mathematics
2 answers:
m_a_m_a [10]3 years ago
3 0

Answer:

1. 260 years

2. 3/6  I think I'm not sure

3. 5:30

4. 50 kg (I think)

5. 5 ft ( 54 in. = 4.5 ft)

6. x = 4

7. 9

8. false

9. Perpendicular

10. 40

Zepler [3.9K]3 years ago
3 0
1. 260 years
2. 3/6
3. 5:30
4. 50kg
5. 5ft
6. X=4
7. 9
8. FALSE
9. Perpendicular
10. 40

I’m sorry if any of these are wrong.
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Mr. Lucpas wased 3/8 of his larundy. His son washed 1/3 of it. Who washed most of the laundry?ahow much of the larndy still need
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7 0
3 years ago
The edge of a cube was found to be 30 cm with a possible error in measurement of 0.2 cm. Use differentials to estimate the maxim
rjkz [21]

Answer:

Maximum volume error = ±540 cm³

Relative error = 0.02

Percentage error = 2%

Step-by-step explanation:

Relative error : The ratio of volume error to the total volume.

Percentage error: The product of relative error and 100.

The volume of a cube is = side^3

v =x³

Differentiate with respect to x

\frac{dv}{dx} = 3x^2

\Rightarrow dv = 3x^2 dx

Here are x = 30 cm and dx= ±0.2 cm

∴ dv = 3×(30 cm)² (±0.2 cm)

      =±540 cm³

The volume of the cube = 30³ cm ³ = 27,000 cm³

Then the relative error

=\frac{dv}{v}

=\frac{540 cm^3}{27,000 cm^3}

= 0.02.

The percentage error

= (0.02×100)

=2%

7 0
3 years ago
Determine what type of model best fits the given situation: Farmer Joe has 1,000 bushels of corn to sell. Presently the market p
3241004551 [841]

Answer:

C. Quadratic model

Step-by-step explanation:

Determine what type of model best fits the given situation: Farmer Joe has 1,000 bushels of corn to sell. Presently the market price for corn is $5.00 a bushel. He expects the market price to increase by $0.15 per week. For each week he waits to sell, he loses ten bushels due to spoilage. A. none of these B. exponential C. quadratic D. linear

Given:

The quantity of corn Farmer Joe has to sell = 1,000 bushels

The present market price for corn = $5.00 a bushel

The amount by which he expects the market price to rise per week =$0.15

The number of bushels lost to spoilage per week = 10

The price of the corn per bushel with time = 5 + 0.15×t

The amount of corn left with time= 1000 - 10×t

Where;

t = Time in minutes

Value of the corn = Amount of corn left × Price of corn

Value of the corn = (1000 - 10×t) × (5 + 0.15×t)

=(1000-10t) × (5+0.15t)

=5,000 + 150t - 50t - 1.5t²

= -1.5t² +100t + 5000

Value of the corn= -1.5t² +100t + 5000.

It is a quadratic model

4 0
4 years ago
(-2x + y - 4) - (-3x - 2y)
svlad2 [7]
(-2x + y - 4) - (-3x - 2y) = x + 3y - 4
7 0
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