The correct answer is rhombus
Let t and s represent the masses of 20% and 60% alloys respectively.
t+s=80, s=80-t
(0.2t+0.6s)/80=0.52 multiply both sides by 80
0.2t+0.6s=41.6, now using s=80-t in this equation gives us:
0.2t+0.6(80-t)=41.6 perform indicated multiplication on left side
0.2t+48-0.6t=41.6 combine like terms on left side
-0.4t+48=41.6 subtract 48 from both sides
-0.4t=-6.4 divide both sides by -0.4
t=16, since s=80-t
s=64
So 16kg of 20% alloy is mixed with 64kg of 60% allow to make 80kg of a 52% alloy.
Answer:
x² is HCF (Height common factor)
Step-by-step explanation:
Given:
x² , x³
Find:
HCF (Height common factor)
Computation:
HCF (Height common factor) is uused to find Height common factor from the given numbers.
x² , x³
Takling x² as common
x² (1 , x)
So,
x² is HCF (Height common factor)
The value of 2 in 2783 (2000) is 10 times the value of two in 7283 (200).
Hope this helped!
Nate
