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postnew [5]
2 years ago
13

How do you explain what y=3^x is?

Mathematics
1 answer:
ololo11 [35]2 years ago
8 0

Step-by-step explanation:

y is equal to 3 times the value of x. for example if x=2 y would equal 6.

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A 6.50% coupon bond with 18 years left to maturity is offered for sale at $1,035.25. What yield to maturity [interest rate] is t
Basile [38]

Answer:

The yield to maturity is 6.3974%

Step-by-step explanation:

The computation of the yield to maturity is as follows

Given that

NPER = 18 × 2 = 36

PMT = $1,035.25 × 6.50% ÷ 2 = $33.65

PV = $1,035.25

FV = $1,000

The formula is shown below:

=RATE(NPER;PMT;-PV;FV;TYPE)

The present value comes in negative

AFter applying the above formula, the yield to maturity is

= 3.1987% × 2

= 6.3974%

Hence, the yield to maturity is 6.3974%

7 0
3 years ago
You get dressed in the morning without looking at the colours of the clothes you choose. Your shirts are white or blue, your pan
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Answer:

add up all the colors

Step-by-step explanation:

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Adam makes $632 gross income per week and has claimed four allowances. According to the table below, what is Adam’s net income a
Paul [167]
The answer is B(533)
7 0
3 years ago
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What is 80% as a fraction in reduced form ?
dangina [55]
4/5 because 8/10 is equal to 4/5 which is the simplest form<span />
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Report Error Suppose $P(x)$ is a polynomial of smallest possible degree such that: $\bullet$ $P(x)$ has rational coefficients $\
motikmotik

Answer:

We want a polynomial of smallest degree with rational coefficients with zeros in \sqrt{7}, 1 - \sqrt{6} and -3. The last root gives us the factor (x+3). Hence, our polynomial is

P(x) =(x+3)q(x)

where q is a polynomial with rational coefficients and roots \sqrt{7} and 1 - \sqrt{6}. The root \sqrt{7} gives us a factor x-\sqrt{7}, but in order to obtain rational coefficients we must consider the factor x^2-7.

An analogue idea works with 1 - \sqrt{6}. For convenience write  x - 1 + \sqrt{6} = ( x - 1) + \sqrt{6}. This gives the factor (x-1)^2-6. Hence,

P(x) = (x+3)(x^2-7)((x-1)^2-6)=x^5+x^4-18x^3-22x^2+77x+105

Notice that P(-1)=24. So, in order to satisfy the last condition we divide by 3 the whole polynomial, without altering its roots. Finally, the wanted polynomial is

P(x) =(1/3)x^5+(1/3)x^4-6x^3-(22/3)x^2+(77/3)x+35

Step-by-step explanation:

We must have present that any polynomial it's determined by its roots up to a constant factor. But here we have irrational ones, in order to eliminate the irrational coefficients that a factor of the type x-\sqrt7 will introduce in the expression, we need to multiply by its conjugate x+\sqrt7. Hence, we will obtain x^2-7 that have rational coefficients. Finally, the last condition is given with the intention to fix the constant factor. Usually it is enough to evaluate in the point and obtain the necessary factor.

4 0
3 years ago
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