Answer:
Pertaining to the yielded interrogate, the retort is 6.30.
Step-by-step explanation:
As disseminated, the terms may equate to the proximate as identified:
-If an inch is equivalent to the numeral equivalence of 2.54, hence 5 inches (in) is in the accordance with the equivalence to 12.7 centimeters (cm).
Alas, the terms may equate as the following:
19 cm - 12.7 cm = x
Thus, as to resolute and evaluate the retort, with respect to your interrogate, is 6.30.
*Hope this helps.
Answer:
B. Solve each equation for a variable
Is (-1,13) a solution of the system: Yes it is x =1, y= 13
Step-by-step explanation:
-4x=30-2y
- 15 = - 2y + 11x
-4x=30-2y
-2y+4y = -30-------------------i
- 2y + 11x= - 15 ---------------ii
make x the subject of formula in equ i
-4x=30-2y
x= (30-2y)/-4
insert x= (30-2y)/-4 in equ ii
- 2y + 11x= - 15
-2y+ 11((30-2y)/-4)= -15
-2y+(330-22y)/4 = -15
-8y+330-22y/4 = -15
-8y-22y+330/4= -15
cross multiply
-30y+330 = 4x-15 = -60
-30y = -60-330
-30y =--390
y= -390/-30 = 13
if y = 13
x = (30-2y)/-4 = (30-2x13)/-4 = (30-26)/4 = 4/4 = 1
x=1 , y=13
Answer:
Step-by-step explanation:
i hopes this helps
We have been given that the lifespans of lions in a particular zoo are normally distributed. The average lion lives 12.5 years; the standard deviation is 2.4 years. We are asked to find the probability of a lion living longer than 10.1 years using empirical rule.
First of all, we will find the z-score corresponding to sample score 10.1.
, where,
z = z-score,
x = Random sample score,
= Mean
= Standard deviation.



Since z-score of 10.1 is
. Now we need to find area under curve that is below one standard deviation from mean.
We know that approximately 68% of data points lie between one standard deviation from mean.
We also know that 50% of data points are above mean and 50% of data points are below mean.
To find the probability of a data point with z-score
, we will subtract half of 68% from 50%.


Therefore, the probability of a lion living longer than 10.1 years is approximately 16%.