Answer: 6 snack bags.
Step-by-step explanation:
For this exercise it is important to remember the Greatest Common Divisor (GCD). This is defined as the largest positive intener by which you can divided evenly "n" numbers.
In this case, you know that Jane has 18 juice boxes, 24 bags of peanuts and 36 apples. Therefore, the steps are the following:
1. You need to descompose 18, 24 and 36 into their prime factors, as below:

2. Now you must choose the common ones with the smallest exponent and multiply them.
Then, you get:

Therefore, the greatest number of snack bags that Jane can make is: 6 snack bags.
Answer:
Roughly
1143$ annually
But if you want exact then its
1142.857143$
Step-by-step explanation:
(x + 6)² (x - 3)²
(x + 6)(x + 6) (x - 3)(x - 3)
x² + 6x + 6x + 36 x² - 3x - 3x + 9
x² + 12x + 36 x² - 6x + 9
First one is -13
second one is 16
4+x=18, the sum would make it an addition problem and x would represent "a number".