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Vikentia [17]
3 years ago
7

PLZ HELP FAST (15 points)​

Mathematics
1 answer:
givi [52]3 years ago
6 0

Answer:

MORE

Step-by-step explanation:

hope this helps can I have brainliest

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Someone help me please with this algebra problem
kvv77 [185]

Answer:

D.

Step-by-step explanation:

She cannot buy a negative number of notebooks. She can buy 0 notebooks, or 1 notebook, or 2, or 3, etc. The number of notebooks she buys must be a non-negative integer.

Answer: D.

6 0
3 years ago
Needs answers <br> Will mark brainliest
Elden [556K]

QUESTION 1:

Required angles are: m<2=75°, m<3=75°, m<4= 105°, m<5= 105°, m<6=75°, m<7=75°, m<8=105°

QUESTION 2:

Required angles are: m<1=100° m<2=80°, m<4= 100°, m<5= 100°, m<6=80°, m<7=80°, m<8=100°

Step-by-step explanation:

Question 1:

if m<1 =105°

We need to find the remaining angles.

The corresponding angles of a traversal are same. so the corresponding angle of <1 is angle 5 So, m<5 = 105°

The vertical angles are also equal. so, vertical angle of <1 is <4. So, m<4 = 105°

Vertical angles of m<5 is m<8 so, m<8=105°

m<1 and m<2 are supplementary angles of each other so their sum will be equal to 180°

So, m<1+m<2=180

105+m<2=180

m<2=75°

Same goes for m<3 and m<4 so, m<3 = 75°

m<5 and m<6 so, m<6 = 75°

m<7 and m<8 so, m<7= 75°

So, required angles are: m<2=75°, m<3=75°, m<4= 105°, m<5= 105°, m<6=75°, m<7=75°, m<8=105°

Question No 2

if m<3=80°

We need to find the remaining angles.

The corresponding angles of a traversal are same. so the corresponding angle of <3 is angle 7 So, m<7 = 80°

The vertical angles are also equal. so, vertical angle of <3 is <2. So, m<2 = 80°

The Vertical angle of <7 is <6 so, m<6= 80°.

m<1 and m<2 are supplementary angles of each other so their sum will be equal to 180°

So, m<1+m<2=180

m<1+80=180

m<1=100°

Same goes for m<3 and m<4 so, m<4 = 100°

m<5 and m<6 so, m<5 = 100°

m<7 and m<8 so, m<8= 100°

So, required angles are: m<1=100° m<2=80°, m<4= 100°, m<5= 100°, m<6=80°, m<7=80°, m<8=100°

Keywords: Traversal of parallel lines

Learn more about traversal of parallel lines at:

  • brainly.com/question/1598227
  • brainly.com/question/3227215
  • brainly.com/question/10483199

#learnwithBrainly

3 0
4 years ago
Form a polynomial whose real zeros and degree are given. ​zeros: negative 2−2​,negative 1−1​,44​, 55​; ​ degree: 4 type a polyno
prisoha [69]
We write the polynomial in its factored form first.
 We have then:
 (x + 2) * (x + 1) * (x-4) * (x-5)
 We now rewrite the polynomial:
 (x ^ 2 + x + 2x + 1) * (x ^ 2-5x-4x + 20)
 (x ^ 2 + 3x + 1) * (x ^ 2-9x + 20)
 x ^ 4 - 9x ^ 3 + 20x ^ 2 + 3x ^ 3 - 27x ^ 2 + 60x + x ^ 2 - 9x + 20
 We now add terms of the same degree:
 x ^ 4 + (-9 + 3) x ^ 3 + (20-27 + 1) x ^ 2 + (60-9) x + (20)
 x ^ 4 + (-6) x ^ 3 + (-6) x ^ 2 + (21) x + (20)
 x ^ 4 - 6x ^ 3 - 6x ^ 2 + 21x + 20
 Answer:
 
The polynomial sought is:
 
x ^ 4 - 6x ^ 3 - 6x ^ 2 + 21x + 20
6 0
4 years ago
Help please............
wariber [46]

Answer: 21 units^2

explanation: mark me brainiest

8 0
3 years ago
Can someone please help
klasskru [66]

Answer:

3.784

Step-by-step explanation:

3 0
3 years ago
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