Answer:
A) sin θ = 3/5
B) tan θ = 3/4
C) csc θ = 5/3
D) sec θ = 5/4
E) cot θ = 4/3
Step-by-step explanation:
We are told that cos θ = 4/5
That θ is the acute angle of a right angle triangle.
To find the remaining trigonometric functions for angle θ, we need to find the 3rd side of the triangle.
Now, the identity cos θ means adjacent/hypotenuse.
Thus, adjacent side = 4
Hypotenuse = 5
Using pythagoras theorem, we can find the third side which is called opposite;
Opposite = √(5² - 4²)
Opposite = √(25 - 16)
Opposite = √9
Opposite = 3
A) sin θ
Trigonometric ratio for sin θ is opposite/hypotenuse. Thus;
sin θ = 3/5
B) tan θ
Trigonometric ratio for tan θ is opposite/adjacent. Thus;
tan θ = 3/4
C) csc θ
Trigonometric ratio for csc θ is 1/sin θ. Thus;
csc θ = 1/(3/5)
csc θ = 5/3
D) sec θ
Trigonometric ratio for sec θ is 1/cos θ. Thus;
sec θ = 1/(4/5)
sec θ = 5/4
E) cot θ
Trigonometric ratio for cot θ is 1/tan θ. Thus;
cot θ = 1/(3/4)
cot θ = 4/3
Answer:
not the best at math but to what I got was 81/3
Step-by-step explanation:
I'[m not 100% sure if that's right but it's what i got so you can be mad if I did do it wrong
Answer:
Step-by-step explanation:
Given:
AB ≅ BC
AK ≅ KC
∠AKE ≅ ∠CKP
To Prove:
ΔAKE ≅ ΔCKP
Statements Reasons
1). AB ≅ BC 1). Given
2). ∠BAC ≅ ∠BCA 2). Property of Isosceles triangles
3). ∠EKA ≅ ∠PKC 3). Given
4). ΔAKE ≅ ΔCKP 4). ASA Postulate of congruence
Hence ΔAKE ≅ ΔCKP.
The initial value of this expression is -3 because the equation is y=mx+b
m=-4x
b=-3
Answer:
p(x) =2(x-1) ^2-8
Step-by-step explanation:
- Add the same value to both sides
- Add 1 to the expression
- Add 2×1 to the left side
- Simplify factors
- Move constant to the right
- Then calculate