All categories

2 years ago

Given the following function, find h(-4) h(x) = 8x2 – 5 h(-4) =

Mathematics

2 answers:

Mila [183]2 years ago

8 0

Step-by-step explanation:

put the value of x in the given function...

scoundrel [369]2 years ago

7 0

Answer:

h(-4) = 123

Step-by-step explanation:

h(x) = 8x² – 5

h(-4) = 8(-4)² - 5

h(-4) = 8(16) - 5

h(-4) = 128 - 5

h(-4) = 123

You might be interested in

14. Team 8A is selling snacks at the football game to raise money for a field trip. They are selling popcorn for $2.50 and pretz

Mamont248 [21]

Answer:

40 popcorns and 90 pretzels sold.

============

Let the number of popcorns is x and pretzels is y.

Set up equations:

x + y = 130
2.5x + 2y = 280

Solve by elimination, multiply the first equation by 2 and subtract from the second equation:

2.5x + 2y - 2x - 2y = 280 - 2*130
0.5x = 280 - 260
0.5x = 20
x = 20/0.5
x = 40

Find y:

40 + y = 130
y = 130 - 40
y = 90

5 0

1 year ago

Read 2 more answers

a hot dog stand sells two type of hot dogs: plain hot dogs and chili-cheese dogs. plain hot dogs code $3 and chili-cheese dogs c

Arte-miy333 [17]

Answer:

i love hotdogs

Step-by-step explanation:

5 0

3 years ago

The number of typing errors made by a typist has a Poisson distribution with an average of three errors per page. If more than t

damaskus [11]

Answer:

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Poisson distribution with an average of three errors per page

This means that $\mu = 3$

What is the probability that a randomly selected page does not need to be retyped?

Probability of at most 3 errors, so:

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498$

$P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494$

$P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240$

$P(X = 3) = \frac{e^{-3}*3^{3}}{(3)!} = 0.2240$

Then

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0498 + 0.1494 + 0.2240 + 0.2240 = 0.6472$

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

3 0

2 years ago

F(x) = 4x-5; f(-2)<br> please help

Firdavs [7]

Answer:

f(x)=-13

Step-by-step explanation:

Substitute x with -2

4 times -2 is -8

-8-5 is -13

Thus f(x)=-13

Hope this helps!

5 0

3 years ago

A fish jumps out of the water at a speed of 12 feet per second. The height y (in feet) of the fish above the surface of the wate

sasho [114]

Answer:

The fish is 2.25 ft above the surface at 0.375 seconds

Step-by-step explanation:

Given:

y=-16x^2+12x

x=0.375 seconds

Substitute x=0.375 into the equation

y=-16x^2+12x

= -16(0.375)^2 +12(0.375

= -16(0.140625) + 4.5

= -2.25 + 4.5

= 2.25

y=2.25 ft

The fish is 2.25 ft above the surface at 0.375 seconds

8 0

3 years ago