5, 3, 2, 6, 5, 2,5 mean: median: mode: range:

Find the number such that twice its square root is 14.

NISA [10]

Answer:

49

Step-by-step explanation:

Let be the unknown number. Twice means times 2. So, the mathematical sentence should be .

Divide both sides by 2.

To remove the radical symbol, raise both sides to the second power.

Thus, the answer is 49. Twice the square root of 49 is equal to 14.

*CREDIT* goes to CebuMath: https://brainly.ph/question/1047782

HE SOLVED THIS NOT ME.

4 0

3 years ago

Read 2 more answers

A manufacturer sells each of his TV sets for $85. The cost C (in dollars) of manufacturing and selling x TV sets per week is C =

igor_vitrenko [27]

Answer: You should produce all 10,000 TV sets to reach the maximum profit.

If you graph the equation for the profit (below), you will see that the function is increasing on the entire interval from 0 to 10,000.
P = 85x - (1500 + 10x + 0.005x^2)

Therefore, the maximum project would be at the end of the interval, or 10,000 TV units.

7 0

3 years ago

Read 2 more answers

1. Determine the quotient: 2 + 13

nlexa [21]

Answer:

15

Step-by-step explanation:

3 0

3 years ago

Will give brainliest, thanks, and 5 stars! LOTS OF POINTS! 50 POINTS!

lubasha [3.4K]

Answer in order:

False

True

False

True

Step-by-step explanation:

All of the solutions to the equation $3x^2 - 12 = 0$ are x = 12 and x = -12

Solve:

Common factor - $3(x^2-4)=0$

Divide both sides

$x^2-4=0$

Use the quadratic formula

$x=\sqrt{4,x}=\sqrt{-4$

x = 2, x = -2

Thus, This is false..

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There are two unique solutions to the equations (x-3)^2 = 16

one variable in matrix = one possible value.

Therefore, x = 7, x = -1

Hence this is True

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The solutions for the equation 2(x-3)^2-18 = 0 are x = 6 and x = 0

$2x^3-18x^2+54x-72=0$

$x=5.080084$

Hence this is false

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The solutions for the equation 2(x-5)^2-8=0 are x = 7 and x = -7

Add both sides by 8

2(x-5)^2-8+8=0+8

2(x-5)^2=8

(x-5)^2=4

x = 7, x = 3

Hence, this is false

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The solutions for the equation (x + 3)^2-25 = -8 are x = 2 and x = -8

$(x+3)^2=17$

$x=\sqrt{17-3,}=-\sqrt{17}-3$

Hence this is false.

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The solutions for the equation 2(2x-1)^2=18 are x = 5 and x = -4

$(2x-1)^2=9$

x=2, x = -1

Hence this is false.

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The only solution for equation (2x-1)^2-49=0 is x = 4

$(2x-1)^2=49$

x = 4, x = -3

Hence, this is false

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The solutions for the equation 3(x+2)^2 - 3 = 0 are x = -3 and x = -1

$3(x+2)^2=3$

$(x+2)^2=1$

x = -1, x = -3

Hence, this is true

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The solutions for the equation 5x^2 - 180 = 0 are x = 6 and x = -6

Add 180 to both sides

$5x^2-180+180=0+180$

$5x^2 = 180$

$x^2 = 36$

$x=\sqrt{36},x=-\sqrt{36}$

x = 6, x = -6

Hence, this is true.

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[RevyBreeze]

7 0

3 years ago

Can any one solve this problem

ElenaW [278]

Answer:

sorry i can't

please mark me as brainlest

6 0

3 years ago

5, 3, 2, 6, 5, 2,5mean:median:mode:range:​

5, 3, 2, 6, 5, 2,5mean:median:mode:range: