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OLga [1]
3 years ago
15

Find the missing length indicated. Please help!!!

Mathematics
1 answer:
natita [175]3 years ago
8 0
C
because if you look at where the unmarked side is divided, the one you’re supposed to find is obviously bigger than the other.
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One zero of the polynomial function f(x) = x3 + x2 + 20x is x = 0. What are the zeros of the polynomial function?
daser333 [38]

Answer:

The correct option is C

Step-by-step explanation:

if f(x)= x3 + x2 - 20x

Replace f(x) by y

y = x3 + x2 - 20x

0 =x3 + x2 - 20x

x3 + x2 - 20x = 0

Take out x as a common:

x(x2+x-20)=0

Find factors of x2+x+20.

x(x^2+4x-5x-20) = 0

x{x(x+4)-5(x+4)}=0

x(x+4)(x-5)=0

Set x= 0

x=0 , x+4=0 , x-5 =0

x=0, x=0-4 , x=0+5

x=0, x= -4, x=5

x=(0,5,-4)

The correct option is C....

6 0
4 years ago
Read 2 more answers
What is the midpoint of (-23,-14) and (-18,2)
zloy xaker [14]

Given two coordinates point 1 as (-23,-14) and point 2 as(-18,2).

To find the midpoint we would use the formula below;

\text{midpoint(x,y)}=(\frac{x_1+x_2_{}_{}}{2},\frac{y_1+y_2}{2})

Where x1=-23, x2=-18, y1=-14, y2=2

We would substitute the values into the midpoint formula.

\begin{gathered} \text{midpoint =(}\frac{-23-18}{2},\frac{-14+2}{2}) \\ =(-\frac{41}{2},-6) \end{gathered}

Therefore, the answer is

\text{midpoint}=(-\frac{41}{2},-6)

7 0
2 years ago
PLZ
g100num [7]

Answer:

21 pairs of socks

Step-by-step explanation:

We can find out how much money Chang has to spend on socks by subtracting the price of sneakers from his total money to spend by solving 160 - 95. From that, we get our answer of $65 that Chang has to spend on socks. We can divide 65 by 3 to see how many pairs of socks he can buy and we get our answer of 21 pairs of socks.

(sorry if it's confusing but I hope it helped anyway)

8 0
3 years ago
Read 2 more answers
Find roots of the equation and state the multiplicity
olya-2409 [2.1K]

({x + 2})^{3}  =  {x}^{3}  + 6 {x}^{2} + 12x + 8
so the answer is
x =  - 2

7 0
3 years ago
I have <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bdx%7D%7Bdt%7D%20%3D%20%20%5Cfrac%7B5%7D%7Bx%7D%20" id="TexFormula1" title=
mojhsa [17]
\bf \cfrac{dx}{dt}=\cfrac{5}{t}\quad ,\quad x(0)=7\to &#10;\begin{cases}&#10;f(t)=0\\&#10;t=7&#10;\end{cases}\\\\&#10;-----------------------------\\\\&#10;\displaystyle \int \cfrac{5}{t}\cdot dt\implies 5\int \cfrac{1}{t}\cdot dt\implies 5ln|t|+C= f(t)&#10;\\\\\\&#10;\textit{now, we know when f(t)=0, t=7}\implies 5ln|7|+C=0&#10;\\\\\\&#10;C=-5ln(7)&#10;\\\\\\&#10;thus\implies \boxed{5ln|t|-5ln(7)=f(t)=x}

notice |7| 7 is positive, so we can simply remove the bars and use 7 by itself

6 0
3 years ago
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