Answer:
Given the information above, the area of the square is 361 cm²
Step-by-step explanation:
A square is a shape with four equal sides. So, in order to find the area of the square, we must find the length of each individual side. We can do this by dividing the perimeter by 4 because a square has 4 equal sides meaning they have the same lengths.
The perimeter of the square is 76. So, let's divide 76 by 4.
76 ÷ 4 = 19
So, the lengths of each sides in the square is 19cm.
In order to find the area, we must multiply the length and the width together. Since a square has equal sides, then we will multiply 19 by 19 to get the area.
19 × 19 = 361
So, the area of the square is 361 cm²
Answer:
the slope is 3,6
Step-by-step explanation:
im a guineas
Answer:
The points are (-16,7),(10,7),(-3,-6) and (-3,20)
Step-by-step explanation:
We have that one endpoint is at (-3,7) and the length is 13 units.
A point that is 13 units horizontally to the left and right will have the same y-coordinate but with x-coordinates that are 13 units from -3.
Hence we have (-16,7) and (10,7)
Also a point that is 13 units vertically up and down will have the same x-coordinate but with y-coordinates that are 13 units from 7.
Hence we again have (-3,-6) and (-3,20)
Answer:
5/11
Step-by-step explanation:
Black= 22 b+17 g
Brown= 4 b +18 g
Blonde= 25 b+ 10 g
Red= 21 b+ 15 g
Total number= 22+17+4+18+25+10+21+15= 132
Number of girls= 17+18+10+15= 60
Girls are 60/132= 2 × 2 × 3 × 5/ 2 × 2 × 3 × 11= 5/11 of all students
Answer:
Step-by-step explanation:
If the liquid is cooling at a constant rate, then the equation for this is linear. We can use the info given to find the linear equation for this situation. We have 2 points: (2, 178) and (5, 154), where the x coordinate represents the time in minutes, and y represents the temperature. We use these values in the slope formula:
Now we will use one of the points to finish writing the equation. I chose (2, 178), but it doesn't matter which one you choose; they will both give you the same equation in the end.
y - 178 = -8(x - 2) and
y - 178 = -8x + 16 so
y = -8x + 196
If we are looking for the temp when the liquid starting cooling, then we are looking for the temp at time 0, or when x = 0 (sincce x is our time).
y = -8(0) + 196 so
y = 196
That's the temp of the liquid before it started any cooling.