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olganol [36]
3 years ago
11

Simplify the equation here:

le="\frac{3}{\sqrt[3]{3} }" alt="\frac{3}{\sqrt[3]{3} }" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
ra1l [238]3 years ago
7 0

Answer:

Below

Step-by-step explanation:

\frac{3}{  \sqrt[3]{3}  }  \\   \frac{ {3}^{ \frac{3}{3} } }{ {3}^{ \frac{1}{3} } }  \\  \\  {3}^{ \frac{2}{3} }  \sqrt[3]{2}

I hope this helps you :)

Kruka [31]3 years ago
6 0

       Step 1: <em>Follow the radical rule.</em>

       \sqrt[n]{a} = a \frac{1}{n}

       Now, you get the number \frac{3}{3\frac{1}{3} }

       Step 2: Follow the exponent rule.

       \frac{x^{a} }{x^{b} } = x^{a-b}

       We get the number 3^{1} - \frac{1}{3}.

       

       Step 3: Finally, we subtract.

       3 - \frac{1}{3} = \frac{2}{3}

       

       The answer is  3 \frac{2}{3}.

     

       Hope this helps :)

       

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