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diamong [38]
2 years ago
8

Please soleeeeeeeeeeeeèeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee​

Mathematics
1 answer:
sineoko [7]2 years ago
8 0

Step-by-step explanation:

Answer is 99. I am pretty sure.

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PLZ HELP GEOMETRY BELOW
katen-ka-za [31]

This is known as Einstein's proof, not because he was the first to come up with it, but because he came up with it as a 15 year old boy.

Here the problem is justification step 2.  The written equation

BC ÷ DC = BC ÷ AC

is incorrect, and wouldn't get us our statement 2, which is correct.

For similar triangles we have to carefully pair the corresponding parts to get our ratios right:

ABC ~ BDC means AB:BD = BC:DC = AC:BC so BC/DC=AC/BC.

Justification 2 has the final division upside down.


7 0
3 years ago
Two boys who live 14 miles apart start at noon to walk toward each other at rates of 3 mph and 4 mph respectively. In how many h
aniked [119]
Since you have the answers given, just track their walking.
After one hour, one guy has covered 3mi and the other 4mi, which is in total 7, not 14
After 2 hours, one guy has covered 6mi and the other 8mi, which is 14mi

The algebraic way would be:
3x +4x = 14 *x being the hour
7x = 14
x =2
6 0
3 years ago
Read 2 more answers
Match the graph with its equation.
victus00 [196]

Answer:

<em>B) -7x + 7y = -49</em>

Step-by-step explanation:

This is a y=x plot/line shifted by 7 units.

This can also be verified plugging in the values of x=0,y=-7 and x=7,y=0. The only equation which satisfies these points in Equation B. These points have been chosen as they're the intercepts of this plot.

6 0
3 years ago
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A survey found that​ women's heights are normally distributed with mean 63.2 in. and standard deviation 2.4 in. The survey also
Effectus [21]

Answer: 99.51%

Step-by-step explanation:

Given : A survey found that​ women's heights are normally distributed.

Population mean : \mu =63.2  \text{ inches}

Standard deviation: \sigma= 2.4\text{ inches}

Minimum height = 4ft. 9 in.=4\times12+9\text{ in.}=57\text{ in.}

Maximum height = 6ft. 2 in.=6\times12+2\text{ in.}=74\text{ in.}

Let x be the random variable that represent the women's height.

z-score : z=\dfrac{x-\mu}{\sigma}

For x=57, we have

z=\dfrac{57-63.2}{2.4}\approx-2.58

For x=74, we have

z=\dfrac{74-63.2}{2.4}\approx4.5

Now, by using the standard normal distribution table, we have

The probability of women meeting the height requirement :-

P(-2.58

Hence, the percentage of women meeting the height requirement = 99.51%

8 0
3 years ago
Write a number sentence to name the difference between point a and point b
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A-b=c
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