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lora16 [44]
2 years ago
5

HELP

Mathematics
1 answer:
loris [4]2 years ago
7 0

Answer:

A) s and t.

Step-by-step explanation:

just trust me. Plus lines s and t are the only pair of lines that don't touch each other and can go on forever not touching each other.

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I need to increase my sales by 35% this month I’m currently at 45 sales how many sales do I need to meet my goal ?
telo118 [61]
Assume that 100% = 45 sales and 35% = X sales amount

You can create a ratio to help you solve for x

45 = 100%
x   =  35 %

Which is equal to this fraction:  (45/x) = (100/35)

Solving for X by cross multiplying and dividing by 100:
  [(45)(35)] / 100  =  X = 15.75 = 16 sales (rounded up)

You would need at least 16 sales to increase sales total by 35%
8 0
3 years ago
Read 2 more answers
Someone please help!
USPshnik [31]
Here are the log properties you need:
log(ab) = log(a) +log(b) \\  \\ log(\frac{a}{b}) = log(a) - log(b) \\  \\ log(a^n) = n log(a)
6 0
3 years ago
What is the coefficient for x in the equation below?
Oliga [24]
The answer a
Because that’s what I said
5 0
3 years ago
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Get this right and you get brainliest
blagie [28]

Answer:

2 1/3 planes

Step-by-step explanation:

3.5 lego planes / 60 minutes

So fraction =

3.5/60

In 40 minutes he will build x planes

So the fraction equation is:

3.5/60 = x/40

Solve:

Cross multiply =

140 = 60x

x = 2 1/3

2 1/3 planes

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

5 0
3 years ago
Help please!!!!!!!!!!!!!!
marshall27 [118]

Step-by-step explanation:

as in the other problem, the table describes mutually exclusive attributes.

so, we can simply sum the numbers up to get the total number of students :

3+9+2+16 = 30 students.

so, when picking a random student, we have 30 possibilities.

now, how many of those 30 have the desired attributes (to have a brother AND a sister) ?

I see 3 in the table.

so, the probability to pick a student that has a brother and a sister is

3/30 = 1/10 = 0.1

3 0
2 years ago
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