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miv72 [106K]
3 years ago
12

Help. I've been staring at this math question for hours. I can't figure it out.

Mathematics
1 answer:
kogti [31]3 years ago
4 0
All the numbers are tilted at a 90 degree angle, except for the number 4 which it tilted at an angle of 89 degrees, hoped this helps
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A high school principal wishes to estimate how well his students are doing in math. Using 40 randomly chosen tests, he finds tha
ollegr [7]

Answer:

99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Step-by-step explanation:

We are given that a high school principal wishes to estimate how well his students are doing in math.

Using 40 randomly chosen tests, he finds that 77% of them received a passing grade.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

                          P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of students received a passing grade = 77%

           n = sample of tests = 40

           p = population proportion

<em>Here for constructing 99% confidence interval we have used One-sample z proportion test statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99  {As the critical value of z at 0.5%

                                           level of significance are -2.5758 & 2.5758}  

P(-2.5758 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 2.5758) = 0.99

P( -2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

P( \hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

<u>99% confidence interval for p</u> = [\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

 = [ 0.77-2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } } , 0.77+2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } } ]

 = [0.5986 , 0.9414]

Therefore, 99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Lower bound of interval = 0.5986

Upper bound of interval = 0.9414

6 0
3 years ago
A construction elevator can carry at most 2,320 pounds. If the elevator operator weighs 195 pounds and each palette of roofing m
zvonat [6]
The maximum number of palettes that the elevator can carry in one trip is 5.

425 times 5= 2,125+ 195= 2,320


Hope this helps!! :-)
6 0
3 years ago
Please help me, i promise its worth it!!!
Rashid [163]

\\ \sf\longmapsto 2(L+B)=55

\\ \sf\longmapsto 2(\dfrac{4}{3}x+x)=55

\\ \sf\longmapsto \dfrac{8}{3}x+2x=55

\\ \sf\longmapsto \dfrac{8x+6x}{3}=55

\\ \sf\longmapsto \dfrac{14x}{3}=55

\\ \sf\longmapsto 14x=165

\\ \sf\longmapsto x=11.78

\\ \sf\longmapsto x\approx 12

Now

  • B=x=12
  • L=4/3(12)=4(4)=16
5 0
3 years ago
Read 2 more answers
What is the SST for the data set (1,5), (2,9), (4,10)
lianna [129]
I think that the answer is (4,10). hope it helped :)
3 0
3 years ago
Read 2 more answers
Analyze the following table of values.<br><br> y=1/2x<br> y=1/2^x2+4<br> y=4^x2+1/2<br> y=4(1/2)x
Fittoniya [83]

The table models an exponential relationship, and the equation of the table is y = 4(1/2)^x

<h3>How to analyze the table of values?</h3>

The table of values is given as:

x  0   1    2   3    4

y  4   2    1   1/2  1/4

The above table shows an exponential model

An exponential model is represented as:

y = ab^x

When x = 0 and y = 4, we have

ab^0 = 4

Evaluate

a = 4

When x = 1 and y = 2, we have

ab^1  = 2

Evaluate

ab  = 2

Substitute 4 for a

4b  = 2

Divide both sides by 4

b = 1/2

Substitute 4 for a and 1/2 for b in y = ab^x

y = 4(1/2)^x

Hence, the equation of the table is y = 4(1/2)^x

Read more about exponential models at:

brainly.com/question/11464095

#SPJ1

6 0
2 years ago
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