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3 years ago

PLZZZZ HEEELLPPP!!!!!!

Mathematics

2 answers:

butalik [34]3 years ago

4 0

Answer is tan inverse6/7

lozanna [386]3 years ago

3 0

Answer:

41°

Step-by-step explanation:

SOHCAHTOA

Sine = Opposite / Hypotenuse

Cosine = Adjacent / Hypotenuse

Tangent = Opposite / Adjacent

tanx = opp / adj

opposite from angle x is 12 centimeter side

adjacent to angle x is 14 centimeter side

the other side is the hypotenuse because it is opposite the right angle

tanx = 12 / 14

use the inverse tangent button (usually press 2nd or shift on calculator and then press tangent button):

Type in calculator: $tan^{-1}(\frac{12}{14})$

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Can anyone help me with this math equation pleasee?

azamat

Answer:

9/20

Step-by-step explanation:

45/100.

5 is a common factor so simplified = 9/20

3 0

3 years ago

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Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt

Paladinen [302]

Answer:

$y(x)=4a\sqrt{3}* sin(x)-3a$

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

$\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}$

But:

$\frac{1}{tan(x)} =cot(x)$

So:

$\frac{dy(x)}{dx} =cot(x)*(3a+y)$

Multiplying both sides by dx and dividing both sides by 3a+y:

$\frac{dy}{3a+y} =cot(x)dx$

Integrating both sides:

$\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx$

Evaluating the integrals:

$log(3a+y)=log(sin(x))+C_1$

Where C1 is an arbitrary constant.

Solving for y:

$y(x)=-3a+e^{C_1} sin(x)$

$e^{C_1} =constant$

So:

$y(x)=C_1*sin(x)-3a$

Finally, let's evaluate the initial condition in order to find C1:

$y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a$

Solving for C1:

$C_1=4a\sqrt{3}$

Therefore:

$y(x)=4a\sqrt{3}* sin(x)-3a$

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4 years ago

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8th grade :
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There will be 4 groups consisting of 17 girls and 12 boys

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4 years ago

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