The quantity of each type of seats sold are as follows:
- Movie and a dinner seat = 200
According to the question,there are four times as many 3D, x seats as Dinner and a Movie, y seats.
That is, x = 4y
Also, total seats
= (x) + (y) + (z) = 3000...….............eqn(1)
Also, If the theater brings in $53,000 when tickets to all 3000 seats are sold.
- 20x + 35y + 15z = 53000...........eqn(2)
By substituting 4y for x in equations 1 and 2; we have;
<em>5y + z = 3000</em>..…........eqn(3) and
<em>115y + 15z = 53000</em>.........eqn(4)
By solving equations 3 and 4 simultaneously; we have;
y = 200 and z = 2000
and since x = 4y
x = 800
The quantity of each type of seats sold is as follows:
- Movie and a dinner seat = 200
Read more:
brainly.com/question/12413726
Answer:
x = 4
Step-by-step explanation:
Step 1: Write out the expression
5(2x - 9) = -5
Step 2: Solve for <em>x</em>
10x - 45 = -5
10x = 40
x = 4
Answer:
the ans is 168.................??????
For this, since 4y - 7 and 2y - 1 are congruent, we can solve for y by setting them equal to each other.
Firstly, subtract 2y on both sides of the equation. 
Next, add 7 on both sides of the equation. 
Finally, divide 2 on both sides of the equation, and your answer will be y = 3
