Question

Please answer this is for my final exam

Answer 1

Answer:

$Slope, m=\frac{2}{3}$

$y = \frac{2}{3}x$

Step-by-step explanation:

The question is not stated.

Possible questions could be

• What is the slope?
• What is the line equation?

So, I'll answer the above general questions

The given points are:

$(x_1,y_1) = (3,2)$

$(x_2,y_2) = (6,4)$

$(x_3,y_3) = (9,6)$

The slope is calculated using:

$m=\frac{y_2 - y_1}{x_2 - x_1}$

This gives:

$m=\frac{4-2}{6-3}$

$m=\frac{2}{3}$

The line equation is calculated using:

$y - y_3 = m(x - x_3)$

This gives:

$y - 6 = \frac{2}{3}(x - 9)$

Open bracket

$y - 6 = \frac{2}{3}x - \frac{2}{3} * 9$

$y - 6 = \frac{2}{3}x - 2*3$

$y - 6 = \frac{2}{3}x - 6$

Add 6 to both sides

$y - 6+6 = \frac{2}{3}x - 6+6$

$y = \frac{2}{3}x$