Somebody help pls Complete the table by filling in the multiplicative inverse of the numbers below
1 answer:
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It has a factor of 2*3*5=30
what is the biggest number that is a multipule of 30
hmm
9000
9900
9990 is the biggest
30*333=9990
the summation of an arithetic sequence where first term is a1 and last is an and the number of terms is n
30 *2=60
that's 2 terms
30*3=90
30,60,90
3 terms
so 30*n means n terms
9990=30*333 means 333 terms
n=333
a1=30
an=9990
s=1668330
answer is 1,668,330
what is the biggest number that is a multipule of 30
hmm
9000
9900
9990 is the biggest
30*333=9990
the summation of an arithetic sequence where first term is a1 and last is an and the number of terms is n
30 *2=60
that's 2 terms
30*3=90
30,60,90
3 terms
so 30*n means n terms
9990=30*333 means 333 terms
n=333
a1=30
an=9990
s=1668330
answer is 1,668,330
<u>Step-by-step explanation:</u>
Use the formula y = A cos (Bx - C) + D where
- A = amplitude
- Period = 2π/B
- Phase Shift = C/B
- D = vertical shift (aka midline)
Given: Max = 8, Min = 2, (1/2)Period = 20 → Period = 40
Amplitude (A) = (Max - Min)/2
= (8 - 2)/2
= 6/2
= 3
Midline (D) = (Max + Min)/2
= (8 + 2)/2
= 10/2
= 5
Period = 2π/B
→ B = 2π/Period
= 2π/40
= π/20
Notice that the Minimum touches the y-axis (not the Max) so there is no phase shift but there is a reflection → C-value = 0 & A-value is negative
Now, let's put it all together:
A = -3, B = π/20, C = 0, D = 5