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qwelly [4]
3 years ago
14

Which expression can be used to find the volume in cubic

Mathematics
1 answer:
zimovet [89]3 years ago
5 0
Volume= a^3 if i understand the question correctly
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Z + 4.6 = 11 sorry again quick answer this :)
Grace [21]
The answer is 6.4,you subtract 4.6 and 11
8 0
4 years ago
Read 2 more answers
Help please
Leno4ka [110]
H = hrs she worked
p = phone calls she answered

h x 10 + p x .25 = maggies earnings

Part A
h x 10 + 60 x .25 = 115

Part B
h x 10 + 15 = 115 (multiplied 60 x .25)
h x10 = 100 (subtracted 15 from each side of the equation)
h = 10 (divided 10 into each side)

Part C
10 hrs

Hope this helps

3 0
3 years ago
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The sum of the squares of the lengths of the sides of a right triangle is equal to the square of the length of the hypotenuse
Karolina [17]
Attached. İf right I'm happy

5 0
3 years ago
Mr. Hedde requires 60% to pass. If someone gets 160 points and falls short by 20
olganol [36]

Answer:

300 points

Step-by-step explanation:

160 + 20 = 180

180 would have been 60 percent

180/60 = 300

300 would have been needed to pass

Proven by:

300 * 60% = 180

180 - 20 = 160

7 0
3 years ago
Consider the differential equation4y'' − 4y' + y = 0; ex/2, xex/2.Verify that the functions ex/2 and xex/2 form a fundamental se
Nina [5.8K]

Step-by-step explanation:

Let y1 and y2 be (e^x)/2, and (xe^x)/2 respectively.

The Wronskian of them functions be

W = (y1y2' - y1'y2)

y1 = (e^x)/2 = y1'

y2 = (xe^x)/2

y2' = (1/2)(x + 1)e^x

W = (1/4)(x + 1)e^(2x) - (1/4)xe^(2x)

= (1/4)(x + 1 - x)e^(2x)

W = (1/4)e^(2x)

Since the Wronskian ≠ 0, we conclude that functions are linearly independent, and hence, form a set of fundamental solutions.

8 0
3 years ago
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