So to do this we need a little trig. picture a slide with a ladder, the slide would be the hypotenuse and the ladder would be the vertical side. and since we know the slide makes a 35 degree angle with ground we can solve by using the cosine function
![\cos(35) = \frac{x}{4.1}](https://tex.z-dn.net/?f=%20%5Ccos%2835%29%20%20%3D%20%20%5Cfrac%7Bx%7D%7B4.1%7D%20)
because cos = opposite/hypotenuse. the opposite side is the ladder in this case. therefore your answer for how high up the slide is
![x = 4.1\cos(35)](https://tex.z-dn.net/?f=x%20%3D%20%204.1%5Ccos%2835%29%20)
Answer:
y = 3x + 5
Step-by-step explanation:
A line in slope-intercept form has the following format:
![y = mx+b](https://tex.z-dn.net/?f=y%20%3D%20mx%2Bb)
Passes through point (2,11)
Means that when x = 2, y = 11. So
![y = mx+b](https://tex.z-dn.net/?f=y%20%3D%20mx%2Bb)
![11 = 2m+b](https://tex.z-dn.net/?f=11%20%3D%202m%2Bb)
Passes through point (4,17)
Means that when x = 4, y = 17. So
![y = mx+b](https://tex.z-dn.net/?f=y%20%3D%20mx%2Bb)
![17 = 4m+b](https://tex.z-dn.net/?f=17%20%3D%204m%2Bb)
From the first equation,
. So
![17 = 4m+b](https://tex.z-dn.net/?f=17%20%3D%204m%2Bb)
![17 = 4m + 11 - 2m](https://tex.z-dn.net/?f=17%20%3D%204m%20%2B%2011%20-%202m)
![2m = 6](https://tex.z-dn.net/?f=2m%20%3D%206)
![m = 3](https://tex.z-dn.net/?f=m%20%3D%203)
Then
![b = 11 - 2m = 11 - 2*3 = 5](https://tex.z-dn.net/?f=b%20%3D%2011%20-%202m%20%3D%2011%20-%202%2A3%20%3D%205)
So the correct answer is:
y = 3x + 5
Answer:
The answer is: ![2x^2-7x-2](https://tex.z-dn.net/?f=2x%5E2-7x-2)
Step-by-step explanation:
we are asked to subtract
from ![2x^2-11](https://tex.z-dn.net/?f=2x%5E2-11)
so,
.
Hence the desired result is:
.
45 min -> 30 pages
1 min -> 2/3 page
3 x 60 min = 180 min
180 min -> 2/3 x 180
= 120 pages
If 12c-18 is the perimeter of a regular hexagon we can divide this by 6 to get the length of one side. (12c-18)/6 = 2c-3 as an expression for one side of the hexagon.
We need an expression that is equal to 12c-18 one possible expression is just 2c-3+2c-3+2c-3+2c-3+2c-3+2c-3 would be equal to 12c-18. The other expression would also have to equal 12c-18 we can divide this expression by to then add that quotient to itself. (12c-18)/2= 6c-9. 6c-9+6c-9
a.2c-3+2c-3+2c-3+2c-3+2c-3+2c-3
b.6c-9+6c-9
c. 2c-3