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Viktor [21]
3 years ago
8

A rectangle is 30 inches long. The diagonal is 50 inches how wide is the rectangle?

Mathematics
2 answers:
Fantom [35]3 years ago
7 0

The answer is 1,500. You have to multiply 30 and 50.

lukranit [14]3 years ago
6 0

Answer:

40

Step-by-step explanation: A rectangle is  a quadralaterial with 4 90 degree angles made up of two diagonals. If we draw one diagonal, it would split the rectangles into two right triangles. Since a rectangle has a right angle, we can use pythagorean theorem to solve the missing side.              

a^{2} +b^{2} =c^{2}   where a and b are the length and widith  and c is the diagonal length. Let plug it in

30^{2} +b^{2} =50^{2}

900+b^{2}=2500

b^{2} =1600

\sqrt{1600 =40

b=40

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20 inches is 400
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So the frequency of a 35 inch string is 700 cycles per second
5 0
3 years ago
Evaluate the determinant for the following matrix [3 -5 / 1 1]
Natalka [10]

Answer:

<h2>A. -2</h2>

Step-by-step explanation:

\det\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] =ad-bc\\\\\det\left[\begin{array}{ccc}3&-5\\1&1\end{array}\right] =(3)(1)+(-5)(1)=3-5=-2

6 0
3 years ago
Y=2x+5 y=3x−1 solve by subsitution
loris [4]

Answer:

(6,17)

Step-by-step explanation:

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^divided by -1 on both sides

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5 0
2 years ago
Geometry help please!
Gekata [30.6K]

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3 0
3 years ago
Find the following integral
ololo11 [35]

There's nothing preventing us from computing one integral at a time:

\displaystyle \int_0^{2-x} xyz \,\mathrm dz = \frac12xyz^2\bigg|_{z=0}^{z=2-x} \\\\ = \frac12xy(2-x)^2

\displaystyle \int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy = \frac12\int_0^{1-x}xy(2-x)^2\,\mathrm dy \\\\ = \frac14xy^2(2-x)^2\bigg|_{y=0}^{y=1-x} \\\\= \frac14x(1-x)^2(2-x)^2

\displaystyle\int_0^1\int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy\,\mathrm dx = \frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx

Expand the integrand completely:

x(1-x)^2(2-x)^2 = x^5-6x^4+13x^3-12x^2+4x

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4 0
2 years ago
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