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Viktor [21]
3 years ago
8

A rectangle is 30 inches long. The diagonal is 50 inches how wide is the rectangle?

Mathematics
2 answers:
Fantom [35]3 years ago
7 0

The answer is 1,500. You have to multiply 30 and 50.

lukranit [14]3 years ago
6 0

Answer:

40

Step-by-step explanation: A rectangle is  a quadralaterial with 4 90 degree angles made up of two diagonals. If we draw one diagonal, it would split the rectangles into two right triangles. Since a rectangle has a right angle, we can use pythagorean theorem to solve the missing side.              

a^{2} +b^{2} =c^{2}   where a and b are the length and widith  and c is the diagonal length. Let plug it in

30^{2} +b^{2} =50^{2}

900+b^{2}=2500

b^{2} =1600

\sqrt{1600 =40

b=40

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The height of the container should be equal to 2.57 cm, so as to minimize cost.

<h3>How to calculate the height?</h3>

First of all, we would determine the volume of the rectangular container by using this formula:

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Where:

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Substituting the given parameters into the formula, we have;

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At a volume of 12 ft³, we have:

12 = 4x²h

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For the total area of top and bottom, we have:

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For the total area of all four sides, we have:

Area = (x × h) + (x × h) + (4x × h) + (4x × h)

Area = xh + xh + 4xh + 4xh

Area = 10xh sq. units.

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Cost = $45xh.

Also, the cost function would be given by:

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Read more on minimum height here: brainly.com/question/27308167

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