Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran
anastassius [24]
(x; y) -> (x - 2; y + 4)
J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)
K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)
L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)
M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)
Answer:
The answer is 2,016
Step-by-step explanation:
4 × 4 × 3 × 2 × 3 × 7= 2,016
Answer:
7.324840764
Step-by-step explanation:
23/3.14=7.324840764
Answer:
5(m + 5) (m - 8)
Step-by-step explanation:
5m2- 15m- 200
Start by pulling 5 out.
5(m^2 - 3m - 40)
We consider all factors of 40
1 40
2 20
4 10
5 8
Based on the middle term we know that 5 and 8 are our best option.
5(m 5) (m 8)
We know the signs have to be one + and one - because a - * - = + and + * + = +
Since 5 - 8 would give us -3 we know that our answer is
5(m + 5) (m - 8)
14th term is the answer bro
