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telo118 [61]
3 years ago
9

What is the first term for an arithmetic sequence with a12 = 56 and a21=101?

Mathematics
1 answer:
Alenkinab [10]3 years ago
4 0
The first term is -43.

Explanation:

an = a + (n - 1)d

a12 = a + 11d = 56, first equation
a21 = a + 20d = 101, second equation

Subtract the second equation from the first equation, cancelling +a and -a
11d - 20d = 56 - 101
-9d = -45
d = 5

Subtitute d into the first equation
a + 99 = 56
a = -43

a refers to the first term, hence the first term is -43.
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Answer: 1. D) 30

2. A) 8

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4. A)  2/9

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Step-by-step explanation:    

1. Since, here the tokens from a bag containing 10 blue tokens, 8 green tokens, and 12 red tokens. The first draw is a green token.

Thus, the total token = 10 blue tokens+ 8 green tokens+ 12 red tokens = 30 token

Therefore, If the first draw is a green token, Then total outcomes that will possible = 30.

2. Since, getting green is an event with 8 favorable outcomes.

Therefore,  If the first draw is a green token, Then total favorable outcomes that will possible = 8.

3. The possibility of getting green in first drawn, P(G) = \frac{8_C_1}{30_C_1}

P(G) =  \frac{8}{30} = \frac{4}{15}

4. Here, Number of red socks= 5

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Therefore total socks = 10

⇒ Probability of picking a pair of red socks,

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⇒ P(R)= 2/9

5. Since, here coin is flipped 50 times and lands on heads 32 times.

Therefore, experimental probability that coin will land on heads on the next flip = (total times in which head appears/ total number of experiments) × 100 = (32/50)×100=64%


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3 years ago
A gardener works 14 hours a week and charges 168. how much does the gardener charge for each hour
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Answer:

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Step-by-step explanation:

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