What is the first term for an arithmetic sequence with a12 = 56 and a21=101?
1 answer:
The first term is -43.
Explanation:
an = a + (n - 1)d
a12 = a + 11d = 56, first equation
a21 = a + 20d = 101, second equation
Subtract the second equation from the first equation, cancelling +a and -a
11d - 20d = 56 - 101
-9d = -45
d = 5
Subtitute d into the first equation
a + 99 = 56
a = -43
a refers to the first term, hence the first term is -43.
You might be interested in
Answer: .....
Step-by-step explanation:
Answer:
D. 6x2^2y^2 + 10xy^2 - 2x^2y^3
Step-by-step explanation:
Answer:
if you're talking about slope intercept then
y= 8/5x + 11/5
If one kilogram is equal to 35.274 then just multiply 1.5 by 35.274.
1.5 * 35.274 = <span>52.911</span>
We meet again
so first divide 60 by 5
this gives 12
then multiply 12 by 4
giving a final answer of 48
