Answer:
By power of a point, AC⋅CB=DC⋅CE. That is, 12⋅12=6⋅(2R–6).
Then, R=15.
Answer:
4y^{2}+3y
Step-by-step explanation:
First you need to distribute the values.
(4y+3)(2y) Using the "Rainbow Method" to multiply the polynomials
You Should get
8y^{2}+6y
Since this is the area of the rectangle and we need to find the area of the shaded region you need to dived 8y^{2}+6y in half because the shaded region is half of the rectangle.
8y^{2}+6y/2
Doing this you will get
4y^{2}+3y
Cylinder SA=2πrh+2πr<span>2
</span>Rectangular prism SA=2(wl+hl+hw)for the cylinder
SA= 904.78
for the rectangular prism
-you know that all the sides are 8 cm
h- 14
w-8
l-8
SA= 576
Add both together and you should get
1480.78
<span>Area of parallelograms
</span><span>We can figure out a formula for the area of a parallelogram by dissecting the parallelogram and rearranging the parts to make a rectangle. Because the parallelogram and rectangle are composed of the same parts, they necessarily have the same area. (See the definition of area for more about why those areas are the same.)
</span>
We can see that they also<span> have exactly the same base length (blue) and exactly the same height (green). Because </span><span>base x height</span><span> gives the area of the rectangle, we can use the same measurements on the parallelogram to compute its area: </span><span>base x height</span><span>. (As before, "height" is measured perpendicular to the base, and "base" is whichever side you chose first. See parallelogram.)
</span>
Area of triangle
Knowing how to find the area of a parallelogram helps us find the area of a triangle.
Dissecting the triangle
We can dissect the triangle into two parts -- one of them a triangle, and one of them a trapezoid -- by slicing it parallel to the base. If we cut the height exactly in half with that slice, the two parts fit together to make a parallelogram with the same base but half the height.
So <span>base x half-height</span><span> gives the area of the triangle. A similar dissection shows </span><span>half-base x height</span><span>. Either of them reduces to 1/2 </span>bh.
The parallelogram's area is base x height, but that is twice the area of the triangle, so the triangle's area is <span>1/2 of base x height</span>, as we saw with the dissection method.
(As always, pick a "base" and measure the height perpendicular to that base, from the base to the opposite vertex.)
hope this helped!
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