Step-by-step explanation:
f(x)=2x²+3x+9
g(x) = - 3x + 10
In order to find (f⋅g)(1) first find (f⋅g)(x)
To find (f⋅g)(x) substitute g(x) into f(x) , that's for every x in f (x) replace it by g (x)
We have
(f⋅g)(x) = 2( - 3x + 10)² + 3(- 3x + 10) + 9
Expand
(f⋅g)(x) = 2( 9x² - 60x + 100) - 9x + 30 + 9
= 18x² - 120x + 200 - 9x + 30 + 9
Group like terms
(f⋅g)(x) = 18x² - 120x - 9x + 200 + 30 + 9
(f⋅g)(x) = 18x² - 129x + 239
To find (f⋅g)(1) substitute 1 into (f⋅g)(x)
That's
(f⋅g)(1) = 18(1)² - 129(1) + 239
= 18 - 129 + 239
We have the final answer as
<h3>(f⋅g)(1) = 128</h3>
Hope this helps you
Answer:
hi im here to help a kid that ask me to help him
19) C
20) C
1) B
Step-by-step explanation:
3x+40=100
subtract 40 from both sides
3x= 60
divide by 3
x=20
each Sweater cost 20
Answer:
(x - 1) (x + 1) (x - 4) (x + 4)
Step-by-step explanation:
actor the following:
x^4 - 17 x^2 + 16
x^4 - 17 x^2 + 16 = (x^2)^2 - 17 x^2 + 16:
(x^2)^2 - 17 x^2 + 16
The factors of 16 that sum to -17 are -1 and -16. So, (x^2)^2 - 17 x^2 + 16 = (x^2 - 1) (x^2 - 16):
(x^2 - 1) (x^2 - 16)
x^2 - 16 = x^2 - 4^2:
(x^2 - 1) (x^2 - 4^2)
Factor the difference of two squares. x^2 - 4^2 = (x - 4) (x + 4):
(x - 4) (x + 4) (x^2 - 1)
x^2 - 1 = x^2 - 1^2:
(x^2 - 1^2) (x - 4) (x + 4)
Factor the difference of two squares. x^2 - 1^2 = (x - 1) (x + 1):
Answer: (x - 1) (x + 1) (x - 4) (x + 4)
Answer:
2 x 2 x 2 x 3
Step-by-step explanation:
Find two numbers that multiply together to form 24:
2 x 12 = 24
Find two numbers that multiply together to form 12, a factor of 24. Replace 12 with these numbers:
2 x (2 x 6) = 2 x 12 = 24
Find two numbers that multiply together to form 6, a factor of 12. Replace 6 with these numbers:
2 x (2 x (2 x 3)) = 2 x (2x6) = 2 x 12 = 24
Two and three cannot be factored any further, therefore the prime factors of 24 are 2, 2, 2, and 3.
