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Harlamova29_29 [7]
3 years ago
10

What is the value of x in the equation shown below.0.25x + 7 = 4(x - 2)​

Mathematics
2 answers:
natka813 [3]3 years ago
8 0

Answer:

x=4

Step-by-step explanation:

0.25x+7=4(x−2)

Use the distributive property to multiply 4 by x−2.

0.25x+7=4x−8

Subtract 4x from both sides.

0.25x+7−4x=−8

Combine 0.25x and −4x to get −3.75x.

−3.75x+7=−8

Subtract 7 from both sides.

−3.75x=−8−7

Subtract 7 from −8 to get −15.

−3.75x=−15

Divide both sides by −3.75.

x=-15/-3.75

Expand -15/-3.75 by multiplying both numerator and the denominator by 100.

x=-1500/-375

Divide −1500 by −375 to get 4.

x=4

Vanyuwa [196]3 years ago
7 0

Answer:

4

Step-by-step explanation:

because if you distribute youll have 4x

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Replace F(x) with y
y=x^3-10x^2+24x
To find the roots replace y with 0.
0=x^3-10x^2-24x
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x^3-10x^2+24x=0
Factor the left side
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The solution is a result of
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What is 2 15/16 Ian’s a decimal?
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One day at 3:00 a.m., the temperature was -13°F in Kodiak, Alaska. At 10:00 a.m., the temperature was 22°F. What was the average
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3 years ago
In the 1990s the demand for personal computers in the home went up with household income. For a given community in the 1990s, th
WITCHER [35]

Answer:

a) 0.5198 computers per household

b) 0.01153 computers

Step-by-step explanation:

Given:

number of computers in a home,

q = 0.3458 ln x - 3.045 ;   10,000 ≤ x ≤ 125,000

here x is mean household income

mean income = $30,000

increasing rate, \frac{dx}{dt} = $1,000

Now,

a) computers per household are

since,

mean income of  $30,000 lies in the range of 10,000 ≤ x ≤ 125,000

thus,

q = 0.3458 ln(30,000) - 3.045

or

q = 0.5198 computers per household

b) Rate of increase in computers i.e \frac{dq}{dt}

\frac{dq}{dt} = \frac{d(0.3458 ln x - 3.045)}{dt}

or

\frac{dq}{dt}=0.3458\times(\frac{1}{x})\frac{dx}{dt} - 0

on substituting the values, we get

\frac{dq}{dt}=0.3458\times(\frac{1}{30,000})\times1,000

or

= 0.01153 computers

6 0
3 years ago
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