The rates of 6/23 and 318/811 for the age groups gives a confidence
interval for the difference snoring rate
<h3>What method is used to calculate the confidence interval for the difference in rate?</h3>
The number of younger age group, n₁ = 48 + 136 = 184
Proportion of the younger adult that snored, = 48 ÷ 184 =
The number of older age group, n₂ = 318 + 493 = 811
Proportion of the older adult that snored, = 318 ÷ 811 =
The confidence interval, CI, for the difference in two rate (proportion) is
given as follows;
The z-score at 96% confidence level is 2.05, which gives;
Which gives;
Minimum value in the interval ≈ -0.206
Interval maximum value ≈ -0.056
The confidence interval for the different in the snoring rates between the younger and the older age is therefore;
CI = (-0.206, -0.056) =
Learn more about the finding the confidence interval for the mean of a sample here:
brainly.com/question/6156233
Answer:
who is lucky
Explanation:
amino acids are molecules that combine to form proteins
sub to tapl :L
I got this answer from someone else but it should answer your question
About 6 days
Step-by-step explanation:
Here the function that shows the population of fish after x weeks,
Where b is any unknown,
If b = 3,
Then, the function is,
Which is a exponentially increasing function,
That having y-intercept = (0,1)
And, horizontal asymptote,
y = 0
End behavior of the function:
As ,
As ,
Thus, by the above information we can graph the given relation.
Now, For at least 100 fish in the pound,
By taking log on both sides,
Thus, after 0.8567 weeks (approx) the fish on the pound will be at least 100.
1 week = 7 days,
0.8567 weeks = 5.9969 days ≈ 6 days
Hence, after 6 days (approx) the fish on the pound will be at least 100.
The most logical and easiest way would be B, use a compass.
Hello.
i believe d) a 12 month suspension is correct
Good Luck!
Have a good day.