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andriy [413]
3 years ago
10

Seth is playing an arcade game. He

Mathematics
1 answer:
umka21 [38]3 years ago
3 0

Answer:

0

Step-by-step explanation:

+25 for the first attempt but -25 for the second

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Earl needs to fill up juice cups for his little brothers birthday party. There are 25 juice cups and each holds 12 fluid ounces.
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It would take 3 bottles. 25 twelve-ounce cups equals out to 300 ounces. There is only 128 ounces in a gallon. 
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WILL MARK BRAINLIST!!!!!!!!!!<br> |a+x|/ 2 − |a−x|/ 2 if a=−2; x=−6
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If those lines are absolute value then the answer is 0 if they are supposed to be parenthesis then the answer is -6
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Graph the quadratic variation if g(x) varies directly with x^2, and g(x) = 75 when x = 5.
Darina [25.2K]

Answer:

Third graph from the top

Step-by-step explanation:

Formula for g(x) is  g(x) = 3 · x∧2

When we replace x=5 in the formula we get:

g(5) = 3 · 5∧2 = 3 · 25 = 75

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What is the slope-intercept form of them equation of a line that passes through (5, -4) and has a slope of 3/4?
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C is correct answer, passes through (5,-1) and also has slope of 3/4



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3 years ago
The function h(t) = -16t^2 + 16t represents the height (in feet) of a horse (t) seconds after it jumps during a steeplechase.
Vladimir79 [104]
A.) To find the maximum height, we can take the derivative of h(t). This will give us the rate at which the horse jumps (velocity) at time t.

h'(t) = -32t + 16

When the horse reaches its maximum height, its position on h(t) will be at the top of the parabola. The slope at this point will be zero because the line tangent to the peak of a parabola is a horizontal line. By setting h'(t) equal to 0, we can find the critical numbers which will be the maximum and minimum t values.

-32t + 16 = 0

-32t = -16

t = 0.5 seconds

b.) To find out if the horse can clear a fence that is 3.5 feet tall, we can plug 0.5 in for t in h(t) and solve for the maximum height.

h(0.5) = -16(0.5)^2 + 16(-0.5) = 4 feet

If 4 is the maximum height the horse can jump, then yes, it can clear a 3.5 foot tall fence.

c.) We know that the horse is in the air whenever h(t) is greater than 0. 

-16t^2 + 16t = 0

-16t(t-1)=0

t = 0 and 1

So if the horse is on the ground at t = 0 and t = 1, then we know it was in the air for 1 second.
7 0
3 years ago
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