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kondor19780726 [428]
3 years ago
5

8-6x=-28 I need help plzzz

Mathematics
2 answers:
Schach [20]3 years ago
3 0
The answer is 6. 8-6(6) = -28.
matrenka [14]3 years ago
3 0

Answer:

6

Step-by-step explanation:

We need to solve the equation .The given equation is ,

→ 8 - 6x = -28

→ -6x = -28-8

→ -6x = -36

→ x = -36/-6

→ x = 6

<h3>• Hence the value of x is 6 .</h3>
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Sadie simplified the expression √54a^7b^3, where a&gt;=0, as shown: √54a^7b^3= √3^2•6•a^2•a^5•b^2•b=3ab √6a^5b
Tamiku [17]

Answer:

We are to find the error made by Sadie and then find the correct simplification.

The error Sadie made is that she wrote a^7 as a^2 * a^5 instead of a^6 * a.

The square root of a^6 is a^3 and so she could have further simplified.

The correct simplification is shown below:

\sqrt{54a^7b^3} = \sqrt{2 * 3 * 3 * 3 * a^6 * a * b^2 * b} \\  \\= \sqrt{3^2 * a^6 * b^2 * 6 * a * b} \\\\= 3a^3b\sqrt{6ab}

4 0
3 years ago
What is 2/3 of the product of 3/8and 16
MA_775_DIABLO [31]

Answer:

4

Step-by-step explanation:

First, multiply 3/8 x 16:

3/8 x 16 = 6

Then find 2/3 of 6:

6/3=2

2x2=4

3 0
3 years ago
Read 2 more answers
(K3+2k2-82k-28)/(k+10)
Ne4ueva [31]

So for this, we will be using synthetic division. To set it up, have the equation so that the divisor is -10 (since that is the solution of k + 10 = 0) and the dividend are the coefficients. Our equation will look as such:

<em>(Note that synthetic division can only be used when the divisor is a 1st degree binomial)</em>

  • -10 | 1 + 2 - 82 - 28
  • ---------------------------

Now firstly, drop the 1:

  • -10 | 1 + 2 - 82 - 28
  •       ↓
  • -------------------------
  •        1

Next, you are going to multiply -10 and 1, and then combine the product with 2.

  • -10 | 1 + 2 - 82 - 28
  •       ↓ - 10
  • -------------------------
  •        1 - 8

Next, multiply -10 and -8, then combine the product with -82:

  • -10 | 1 + 2 - 82 - 28
  •       ↓ -10 + 80
  • -------------------------
  •        1 - 8 - 2

Next, multiply -10 and -2, then combine the product with -28:

  • -10 | 1 + 2 - 82 - 28
  •       ↓ -10 + 80 + 20
  • -------------------------
  •        1 - 8 - 2 - 8

Now, since we know that the degree of the dividend is 3, this means that the degree of the quotient is 2. Using this, the first 3 terms are k^2, k, and the constant, or in this case k² - 8k - 2. Now what about the last coefficient -8? Well this is our remainder, and will be written as -8/(k + 10).

<u>Putting it together, the quotient is k^2-8k-2-\frac{8}{k+10}</u>

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3 years ago
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Determine the missing exponent<br>2^5=1/4​
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Answer:

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