The approximate area of the decagon with a side of 8cm comes to be 492.40 cm².
The side of the regular decagon = 8cm
<h3>What is a regular decagon?</h3>
A regular decagon is a polygon with 10 sides that are equal to each other.
The area of a regular decagon with side a is:
So, the area A of the regular decagon with a side of 8cm:
A=492.40 cm²
Therefore, the approximate area of the decagon is 492.40 cm².
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Answer:
The x-intercept is (18/5, 0).
The y-intercept is (0,-2).
Step-by-step explanation:
To find the <u>x-intercept</u>, sub y for 0.
-5x + 9y = -18
-5x + 9(0) = -18
Simplify and isolate x.
-5x = -18 <= Divide both sides by -5
x = 18/5
Since we substituted y for 0, y=0.
(18/5, 0)
To find the <u>y-intercept</u>, sub x for 0.
-5x + 9y = -18
-5(0) + 9y = -18
Simplify and isolate y.
9y = -18 <= Divide both sides by 9
y = -2
Since we substituted x for 0, x=0.
(0,-2)
Answer:
vertical asymptote at x=2 and x=-1
Step-by-step explanation:
To find out vertical asymptote we set the denominator =0 and solve for x
now factor left hand side
find out two factors whose product is -2 and sum is -1
-2 times 1 = -2
-2+1 = -1
(x-2)(x+1) =0
x-2 =0 so x= 2
x+1 =0 so x=-1
vertical asymptote at x=2 and x=-1
6 units because 5 is 6 units away from -1
