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12345 [234]
3 years ago
9

Complete the paragraph to show how you can solve problems involving equivalent expressions.

Mathematics
2 answers:
miv72 [106K]3 years ago
8 0

Answer:

Step-by-step explanation:

Model the expressions

with bar models or algebra tiles to determine if the expressions are

Equivalent.

You can also write equivalent expressions using

properties of operations

and order of operations.

m_a_m_a [10]3 years ago
7 0

Answer:

Step-by-step explanation:

Blank 1

Model the expressions.

Blank 2 options.

Equivalent.

Blank 3 options.

properties of operations.

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Nataly [62]

Answer:

The probability of drawing the first pink ball is \frac{3}{10}.

Because you drew that first pink ball, there are two pink balls left and the total number of balls left is nine.

Hence, the probability of drawing another pink ball after drawing the first pink ball would be:

\frac{3}{10} *\frac{2}{9} =\frac{1}{15}

5 0
3 years ago
HURRY I NEED HELP SOON
Juliette [100K]

Answer:

(Sorry in advance if its wrong so don't get mad) but I think its d

Step-by-step explanation:

8 0
4 years ago
Eddie's salary is $3500 per month. Find the Eddie's earnings per year
Vikki [24]

42,000  if he earns 3500 per month just multiply that times 12 which is the amount of months in a year and you get $42,000

8 0
3 years ago
Read 2 more answers
A crawling tractor sprinkler is located as pictured below, 100 feet South of a sidewalk. Once the water is turned on, the sprink
deff fn [24]

Answer:

  a) see below

  b) 32 minutes after turn-on

  c) 52 minutes after turn-on

  d) 20 minutes

  e) 6856.6 ft²

Step-by-step explanation:

a) We have elected to put the origin at the point where the hose crosses the south edge of the sidewalk. Units are feet. Then the sprinkler starts at (0, -100). After 1 hour, 3600 seconds, the sprinkler is 1800 inches, or 150 ft north of where it started, so stops at (0, 50).

The lines forming the sidewalk boundaries are y=0 and y=10.

__

b) Water will first strike the sidewalk when the sprinkler is 20 feet south of it, or 80 feet north of where it started. The sprinkler travels that distance in ...

  (80 ft)(12 in/ft)/(1/2 in/s)(1 min/(60 s)) = 32 min . . . time to start sprinkling sidewalk

__

c) The sprinkler has to travel to a point 130 ft north of its starting position for the water to fall north of the sidewalk. That distance is traveled in ...

  (130 ft)(2/5 min/ft) = 52 min . . . time until end of sprinkling sidewalk

Note that we have combined the scale factors in the expression of part b into one scale factor of (2/5 min/ft).

__

d) The difference of times in parts b and c is the time water falls on the sidewalk: 20 minutes.

__

e) In one hour, the sprinkler travels a distance of ...

  (60 min)(5/2 ft/min) = 150 ft

Of that distance, 10 feet is sidewalk. So, the sprinkler covers an area of grass that is a 140 ft by 40 ft rectangle and a circle of 20 ft radius. The total area of that is ...

  A = LW + πr² = (140 ft)(40 ft) +π(20 ft)² = (14+π)(400) ft² ≈ 6856.6 ft²

The area of grass watered in 1 hour is about 6856.6 ft².

5 0
4 years ago
Answer need help plz
castortr0y [4]
B is the right answer ☺️
6 0
3 years ago
Read 2 more answers
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