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12345 [234]
3 years ago
9

Complete the paragraph to show how you can solve problems involving equivalent expressions.

Mathematics
2 answers:
miv72 [106K]3 years ago
8 0

Answer:

Step-by-step explanation:

Model the expressions

with bar models or algebra tiles to determine if the expressions are

Equivalent.

You can also write equivalent expressions using

properties of operations

and order of operations.

m_a_m_a [10]3 years ago
7 0

Answer:

Step-by-step explanation:

Blank 1

Model the expressions.

Blank 2 options.

Equivalent.

Blank 3 options.

properties of operations.

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In Juan's coin bank there are nickels (n),
alukav5142 [94]

Answer:

The answer is 8 quarters, 16 nickles, and 32 dimes

Step-by-step explanation:

  1. First, the equation would be (2/4d) x 5 +d x 10 +1/4d x 25= 600 (Don't put 6.00, that's dollars. We put 6 dollars into cents to make it easier.)
  2. Then we slowly start to solve: 10/4d + 10d + 25/4d = 600
  3. 10d+40d+25d/4 = 600 (Put all of that over 4, not first 25d)
  4. 75d= 600 x 4
  5. d=600 x 4/75 (same here put everything over 75)
  6. d=32
  7. So then n= 2 x 32/4 = 16
  8. Then n would be equal to : 1/4d= 1/4 x 32 = 8
  9. So your answer would be 8 quarters, 16 nickles, and 32 dimes.

Hope this helped :)

5 0
3 years ago
What formulas can you use to find the point P(x, y) along the line segment between A(x1 , y1 ) and B(x2 , y2 ) that is a fractio
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Answer: Walk through writing a general formula for the midpoint between two points. ... I believe you would simply find the differences in x and y from the midpoint to the one ... How would you solve a problem in which you do not know point B but are given ... the line y=x and the curve y=4x-x^2 intersect at the point p and q.

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7 0
3 years ago
Which expression is equivalent to 3d + 1?
weqwewe [10]

Answer:

3d + 1

I'm pretty sure it's the same thing.

4 0
3 years ago
If you placed $1,000.00 in a savings account with an interest rate of 4.5% month versus an account with 3.75% month, how much in
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The answer would be C. Hope this helps!

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