Answer:
The bus would be 36 times late in 400 times of when Fred takes the bus
Step-by-step explanation:
Given that the probability of being the bus late is 0.09.
In order to find the number of times the bus will be late will be calculated by multiplying the total number of observations by probability.
It is also given that the total number of days he waits for bus is 400 times.
So,
The bus will be:
Hence,
The bus would be 36 times late in 400 times of when Fred takes the bus
0.1257 is a terminating decimap
The equivalent number to the given expanded form is 203.403
<u>Step-by-step explanation</u>:
To find the equivalent number of the expanded form, Use BODMAS rule.
B - bracket
O - of
D - division
M - multiplication
A - addition
S - subtraction
In the given equation, look for the BODMAS order to solve the expanded form:
<u>step 1</u>: solve the numbers inside the bracket.
(2*100)+(3*1)+(4*1/10)+(3*1/1000) = 200 + 3 + 4/10 + 3/1000
<u>step 2</u>: In the order of BODMAS, division comes before addition. So, Division has to be given priority and then addition should be performed.
200 + 3 + 0.4 + 0.003 = 203.403
F(2) will equal 37 then plug it in where x is
13.00 I think I don’t know if that correct but that’s what I got
