60 bottles required.
<h3>
calculate the volume of both shapes</h3>
<u>For hemispherical bowl</u>:
[diameter: 30 cm, radius: 15 cm]
![\rightarrow \sf volume: \dfrac{2}{3} \pi (15)^3](https://tex.z-dn.net/?f=%5Crightarrow%20%5Csf%20volume%3A%20%5Cdfrac%7B2%7D%7B3%7D%20%5Cpi%20%2815%29%5E3)
![\rightarrow \sf volume: 2250\pi \ cm^3](https://tex.z-dn.net/?f=%5Crightarrow%20%5Csf%20volume%3A%202250%5Cpi%20%20%5C%20cm%5E3)
<u>For each </u><u>cylindrical </u><u>bottles</u>:
["r" is 2.5 cm, "h" is 6 cm]
![\rightarrow \sf volume: \pi (2.5)^2(6)](https://tex.z-dn.net/?f=%5Crightarrow%20%5Csf%20volume%3A%20%5Cpi%20%282.5%29%5E2%286%29)
![\rightarrow \sf volume: 37.5 \pi \ cm^3](https://tex.z-dn.net/?f=%5Crightarrow%20%5Csf%20volume%3A%2037.5%20%5Cpi%20%20%5C%20cm%5E3)
<u>So number of </u><u>required bottles</u>:
- volume of hemisphere/volume of each cylindrical bottle
Answer:
(2,5)
Step-by-step explanation:
The answer is 12.2129
Sin(40)=x/19
*19 *19
12.2129=x