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3 years ago

John and his brother, Ricky, decide to combine their money to purchase a television and video game

Mathematics

1 answer:

Tomtit [17]3 years ago

8 0

Answer:

Well, Each of them will have raise $275

Step-by-step explanation:

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I NEED HELP ON THIS PROBLEM!!! PLEASE

Allushta [10]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$5x+8y=-9\implies 8y=-5x-9\implies y=\cfrac{-5x-9}{8} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{5}{8}} x-9\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

well then, so since this equation has that slope therefore

$\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{-5}{8}} ~\hfill \stackrel{reciprocal}{\cfrac{8}{-5}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{8}{-5}\implies \cfrac{8}{5}}}$

so we're really looking for the equation of a line whose slope is 8/5 and runs through (10,10)

$(\stackrel{x_1}{10}~,~\stackrel{y_1}{10}) ~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{8}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{\cfrac{8}{5}}(x-\stackrel{x_1}{10})$

5 0

3 years ago

Gena wants to estimate the quotient of –21.87 divided by 4.79. Which expression shows the best expression to estimate the quotie

Mkey [24]

Answer:

-20 divided 5 is the right answer.

Your welcome!

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Please help i don’t understand this

sergij07 [2.7K]

yes it does have enough to cover the cube

8 0

3 years ago

F(x)=x2-10 and g(x)=11-x find (f-g)(x)(f-g)(10) and (f/g)(x) if they exist

tester [92]

Answer:

$(f - g)(x) = x^2 + x-21$

$(f - g)(10) = 89$

$(f/g)(x) = \frac{x^2 - 10}{11 - x}$

Step-by-step explanation:

Given

$f(x) = x^2 - 10$

$g(x) = 11 - x$

Solving (1): (f-g)(x)

$(f - g)(x) = f(x) - g(x)$

Substitute values for f(x) and g(x)

$(f - g)(x) = x^2 - 10 - (11 - x)$

Open Bracket

$(f - g)(x) = x^2 - 10 - 11 + x$

$(f - g)(x) = x^2 -21 + x$

Reorder

$(f - g)(x) = x^2 + x-21$

Solving (2): (f-g)(10)

In (1)

$(f - g)(x) = x^2 + x-21$

So:

$(f - g)(10) = 10^2 + 10-21$

$(f - g)(10) = 100 + 10-21$

$(f - g)(10) = 89$

Solving (3): (f/g)(x)

$(f/g)(x) = \frac{f(x)}{g(x)}$

Substitute values for f(x) and g(x)

$(f/g)(x) = \frac{x^2 - 10}{11 - x}$

6 0

3 years ago

Use the change of base rule to find the logarithm to four decimal places. (2 points) log base nine of 0.877.

stealth61 [152]

Alright, this question is a bit confusing, but hopefully this will help:

Remember that Log(a) B = C is actually a^C = B. (Just imagine "a" as the little number that is first written after "Log.")

So here, I think Log(9) 0.877 = "x." And you want the value "x."

9^x = 0.877, which is all I've got, cause I don't really know what this "change of base rule" is. But I hope I helped.

3 0

4 years ago

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