Answer:
The probability that the last card dealt is an ace is 
.
Step-by-step explanation:
Given : A deck of ordinary cards is shuffled and 13 cards are dealt.
To find : What is the probability that the last card dealt is an ace?
Solution :
There are total 52 cards.
The total arrangement of cards is 52!.
There is 4 ace cards in total.
Arrangement for containing ace as the 13th card is 
.
The probability that the last card dealt is an ace is
Therefore, the probability that the last card dealt is an ace is .
To find the Mean or Average you have to add up all numbers it is asking for which in case are 222 and 198.
so you will add 222+198
That will equal 420
Then you will divide with the amount added together which is 2
420/2=210
so the mean of the 11 people is 210 or 210lbs
Answer:
31
Step-by-step explanation:
The Range is the difference between the lowest and highest values (3, 34)
2x+3m=p because you don't know how many people there are you put a variable in place for that
Answer: D
Step-by-step explanation:
Standard Deviation σ2 =
Σ(xi - μ)2/N
=(1 - 5.3)2 + ... + (9 - 5.3)2/10
=68.1/10
= 6.81
σ = √6.81
= 2.60959767014
B) σ2 =
Σ(xi - μ)2/N
=(3 - 61.7)2 + ... + (99 - 61.7)2/10
=58414.1/10
= 5841.41
σ = √5841.41
= 76.429117488036
C) (1 - 11.4)2 + ... + (1 - 11.4)2/10
=8758.4/10
= 875.84
σ = √875.84
= 29.59459410095
D) (79 - 79)2 + ... + (79 - 79)2/10
=0/10
= 0
σ = √0
= 0
I hope this helps, mark as Brainliest please.
