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hoa [83]
2 years ago
10

Kendrick caught 22 rainbow trout and 18 tiger trout while fishing last month. What percent of the trout were tiger trout?

Mathematics
2 answers:
wel2 years ago
8 0

Answer:81%

Step-by-step explanation:

MaRussiya [10]2 years ago
3 0

Answer:

60% tiger trout

Step-by-step explanation:

First, do 22+18=  40

Then, when doing % its always out of 100. So, 100 - 40= 60%

Which means, there were 60% Tiger trout.                                                                                                                                                            

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Step-by-step explanation:

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3 years ago
PLEASE HELP ASAP ILL GIVE BRAINLIEST!!!!!<br><br>find measure of arc MK​
Gwar [14]

Answer:

Arc length MK = 15.45 units (nearest hundredth)

Arc measure = 58.24°

Step-by-step explanation:

Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)

ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

\sf \cos(\theta)=\dfrac{A}{H}

where:

  • \theta is the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Given:

  • \theta = ∠KLM
  • A = LN = 8
  • H = KL = 15.2

\implies \sf \cos(KLM)=\dfrac{8}{15.2}

\implies \sf \angle KLM=\cos^{-1}\left(\dfrac{8}{15.2}\right)

\implies \sf \angle KLM=58.24313614^{\circ}

Therefore, the measure of arc MK = 58.24° (nearest hundredth)

\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right) \quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle)}

Given:

  • r = 15.2
  • ∠KLM = 58.24313614°

\implies \textsf{Arc length MK}=2 \pi (15.2)\left(\dfrac{\sf \angle KLM}{360^{\circ}}\right)

\implies \textsf{Arc length MK}=\sf 15.45132428\:units

6 0
2 years ago
Jarvis works in a garage £6 an hour. If he works on Saturday, he is paid time and a quarter. If he works on Sunday, he is paid t
xxMikexx [17]

Answer: He is paid $90 last weekend.

Step-by-step explanation:

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5 0
3 years ago
A certain antihistamine is often prescribed for allergies. A typical dose for a 100​-pound person is 25 mg every six hours. Comp
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Given that a certain antihistamine is often prescribed for allergies.

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Hence number of 12.8mg chew able tablets would be taken in a week is 55.

b) Now we can use earlier answer for this problem, since 12.8mg tablet is replaced with 9ml liquid, 55 bottles of 9ml liquid are to be taken in a week.

Hence amount of liquid histamine should a 100-pound person take in a week = 55X9

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