We can write this as the difference of squares:
(5b⁸+8c)(5b⁸-8c)
To write as the difference of squares, take the square root of each term first:
√25b¹⁶ = 5b⁸; √64c² = 8c
Now we write this as a sum in one binomial and a difference in the other:
(5b⁸+8c)(5b⁸-8c)
Answer:
8640
Step-by-step explanation:
Answer:
600
Step-by-step explanation:
(1 / 10) * 6000
That's it!
7y + 10x = 99
y - x = 2
y = 7 , x = 5
Answer:
switched signs around
Step-by-step explanation:
I believe that s/he switched the signs around so
|x|>5 is solved by x<-5 and x>5
but I'm not quite sure, sorry
