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Crank
3 years ago
9

Driving is expensive. Write a program with a car's miles/gallon and gas dollars/gallon (both doubles) as input, and output the g

as cost for 20 miles, 75 miles, and 500 miles. Output each floating-point value with two digits after the decimal point, which can be achieved by executing cout << fixed << setprecision(2); once before all other cout statements.
Computers and Technology
1 answer:
zepelin [54]3 years ago
8 0

Answer:

Explanation:

The following is written in C++ and asks the user for inputs in both miles/gallon and dollars/gallon and then calculates the gas cost for the requested mileages using the input values

#include <iostream>

#include <iomanip>

using namespace std;

int main () {

   // distance in miles

   float distance1 = 20.0, distance2 = 75.0, distance3 = 500.0;

   float miles_gallon, dollars_gallon;

   cout << "Enter cars miles/gallon: "; cin >> miles_gallon;

   cout << "Enter cars dollars/gallon: "; cin >> dollars_gallon;

   cout << "the gas cost for " << distance1 << " miles is " << fixed << setprecision(2) << (float) dollars_gallon * distance1 / miles_gallon << "$\n";

   cout << "the gas cost for " << distance2 << " miles is " << fixed << setprecision(2) << (float) dollars_gallon * distance2 / miles_gallon << "$\n";

   cout << "the gas cost for " << distance3 << " miles is " << fixed << setprecision(2) << (float) dollars_gallon * distance3 / miles_gallon << "$\n";

   return 0;

}

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Write a C++ program to count even and odd numbers in array. The array size is 50. The array elements will be entered by the user
vlabodo [156]

Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

int main(){

   int numbers[50];

   int evekount = 0, odkount = 0;

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}

Explanation:

This declares the integer array of number

   int numbers[50];

This initializes the even count and odd count to 0

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This iterates from 1 to 50

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This gets input for the array

       cin>>numbers[i];

This checks for even

<em>        if(numbers[i]%2==0){            evekount++;        }</em>

This checks for odd

<em>        else{            odkount++;        }</em>

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This prints the even count

   cout<<"Even Count: "<<evekount<<endl;

This prints the odd count

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