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3 years ago

Simplify:

Mathematics

1 answer:

ozzi3 years ago

3 0

Its the B because 6.5q-5.6q-0.9q =0
19.7+4.3=24
and p=6.5

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Julie made $22,$55,38,25 how much did she made ?

Dennis_Churaev [7]

Are you trying to add together everything she made in a span of time? If so:
22 + 55 + 38 + 25 = 140

7 0

3 years ago

PLSSS HLEPP ME OUTT ITS URGENTTTT

Nuetrik [128]

Answer:

$P(B) = \frac{4}{18} = \frac{2}{9} = 0.2$

Step-by-step explanation:

Sample space 2+5+7+4=18

3 0

3 years ago

Read 2 more answers

A local car wash is open 8 hours each day. It uses 1/3 of a container of wax for each car. The car wash waxes an average of 8 1/

sweet-ann [11.9K]

Answer:

22.67 containers.

Step-by-step explanation:

The number of cars washed is the average by the total hours worked:

$C_{total}=\bar xt,\bar x=8.5,t=8\\\\C_{total}=8.5\times 8=68$

Given that each car uses 1/3 tin of wax, the total containers is calculated as:

$Containers=\bar x_c n,n=68,\bar x_c=\frac{1}{3}\\\\=\frac{1}{3}\times 68\\\\=22.67$

Hence, the car wash uses 22.67 containers of wax per day.

8 0

3 years ago

Which of the following is the general term for the sequence? -a, a^2, -a^3, a^4,...

Elis [28]

Answer:

The answer would be $-a(-a)^{n-1}$ .

Step-by-step explanation:

We can simply substitute the terms into this equation. Checking the 1st term, $-a(-a)^{1-1} = -a(-a)^{0} = -a(1) = -a$ . Moving on to the second term, we see $-a(-a)^{2-1} = -a(-a)^{1} = -a(-a) = a^{2}$ . And so on and so forth. We can see how the answer fluctuates between negative and positive, while gaining one more exponent every term, which fits with the sequence given. Therefore, the answer would be $-a(-a)^{n-1}$ .

Hope this helped!

8 0

3 years ago

Find the surface area of a 7.4 cm long iron rod and 3.1 m radius

Debora [2.8K]

Answer:

144.2 cm

Step-by-step explanation:

Length of the iron rod is 7.4cm

Radius is 3.1m

Therefore the surface area can be calculated as follows

= 2πrl

= 2×3.142×3.1×7.4

= 144.2 I'm

Hence the surface area is 144.2cm

3 0

3 years ago