When we have a quadratic equation form ax² + bx + c = 0, we have rule
x₁ + x₂ = -b/a
x₁ × x₂ = c/a
x₁ and x₂ are the roots
Given from question:
⇒ x₂ = 2 + x₁
⇒ quadratic equation x² - 4x + c = 0
Solution A:
Determine a,b,c
a = 1
b = -4
c = c
Find the roots with the rule of x₁ + x₂ = -b/a
x₁ + x₂ = -b/a
x₁ + 2 + x₁ = -(-4)/1
2x₁ + 2 = 4
2x₁ = 4 - 2
2x₁ = 2
x₁ = 1
One of the roots is 1
Now find the other root
x₂ = 2 + x₁
x₂ = 2 + 1
x₂ = 3
The other root is 3
Solution B:
Find the constant c by the rule x₁ × x₂ = c/a
x₁ × x₂ = c/a
1 × 3 = c
c = 3
The constant is 3
Use Slader.com, Find the math book and look up the page. It will show you the answer and how to get it.
Answer:
64°
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Answer:
(x = -11 and y = 56) or (x = 1 and y = -4)
Step-by-step explanation:
The equation of the parabola is 10 + y = 5x + x² ........(1)
And 5x + y = 1 ....... (2) is the straight line.
We have to find solutions to equations (1) and (2).
Now, solving equations (1) and (2) we get, 10 + (1 - 5x) = 5x + x²
11 - 5x = 5x +x²
x² + 10x - 11 = 0
(x + 11) (x - 1) = 0
Hence, x = -11 or x = 1
Now, from equation (2),
y = 1 - 5x = 1 - 5(-11) = 56 {When x = -11}
And, y = 1 - 5(1) = -4 (When x = 1}
Therefore, the solution of the system are (x = -11 and y = 56) or (x = 1 and y = -4) "Answer"
All done