Answer:
h(8q²-2q) = 56q² -10q
k(2q²+3q) = 16q² +31q
Step-by-step explanation:
1. Replace x in the function definition with the function's argument, then simplify.
h(x) = 7x +4q
h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q
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2. Same as the first problem.
k(x) = 8x +7q
k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q
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Comment on the problem
In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...
h(8q² -2q) = 56q² -14q +4z
and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.
In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.
Answer:
11.x=16 12.x=37
Step-by-step explanation:
11.
20^2-12^2=x^2
256=x^2
x=√256
x=16
12.
13^2-5^2=y^2
144=y^2
y=12
/
y^2+35^2=x^2
12^2+35^2=x^2
1369=x^2
x=37
Underoot 60 =
7.75 is the answer to your question!
Answer:
b^36
Step-by-step explanation:
Answer:
curtiss can buy 7 pounds of pistachios
Step-by-step explanation:
5 cappuccinos x $5 = 25, 32 - 25=7
