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3 years ago

The relationship between the number of pounds (lb) of trail mix and the price

Mathematics

1 answer:

Norma-Jean [14]3 years ago

5 0

I think it should be B, let me know if it’s right

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Written in standard form -3 x 2 x a + 5 ( - 7b) + ( 12 x c x 4 )

enot [183]

I believe it’s -6ax - 35b + 48c, sorry if it’s wrong

4 0

3 years ago

I need to find t<br> -13.9t-22.3=30.8t+2

Mars2501 [29]

Answer:

t=−0.543624 lemme know if i was right

Step-by-step explanation:

3 0

3 years ago

2m+5=5(m-7)-3m equals??

Svetradugi [14.3K]

2m+5=5(m-7)-3m
first, use distributive property...
2m+5=5m-35-3m
next, combine like terms on the right side...
2m+5=2m-35
next, subtract 2m from both sides.
2m+5=2m-35
-2m -2m
you will get....
5=-35 in which is not true. This means the equation has no solution.

6 0

3 years ago

Read 2 more answers

A stadium has 50,000 seats. Seats in section A cost $30, seats in section B cost $24, and seats in section C cost $18. the numbe

svetoff [14.1K]

Answer:

Section A = 25,000 seats

Section B = 14,600 seats

Section C = 10,400 seats

Step-by-step explanation:

Total Seats = 50,000

Seats in Section A cost = $30

Seats in Section B cost = $24

Seats in Section C cost = $18

Total sales from the event = $1,287,600

No. of Seats in section A = No. seats in Section B + No. seats in Section C

A = B + C

or, 2A = 50,000

A = 25,000 seats @ $30/seat = $750,000

B + C = 25,000

24B + 18C = 537,600

24B + 18(25,000 - B) = 537,600

24B + 450,000 - 18B = 537,600

6B = 87600

B = 14,600

C = 10,400

Hence;

A = 25,000 seats

B = 14,600 seats

C = 10,400 seats

7 0

3 years ago

For a medical study, a researcher wishes to select people in the middle 60% of the population based on blood pressure.

Finger [1]

Answer:

Lower limit: 113.28

Upper limit: 126.72

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 120, \sigma = 8$