Explanation:
Since {v1,...,vp} is linearly dependent, there exist scalars a1,...,ap, with not all of them being 0 such that a1v1+a2v2+...+apvp = 0. Using the linearity of T we have that
a1*T(v1)+a2*T(v1) + ... + ap*T(vp) = T(a1v19+T(a2v2)+...+T(avp) = T(a1v1+a2v2+...+apvp) = T(0) = 0.
Since at least one ai is different from 0, we obtain a non trivial linear combination that eliminates T(v1) , ..., T(vp). That proves that {T(v1) , ..., T(vp)} is a linearly dependent set of W.
Answer:
A.Both of the students did the problem correctly.
Step-by-step explanation:
B. Nikki multiplied the fraction(8/3) to the items in the parentheses. Then multiplied each side with 3. Jon did the opposite. He first removed the fraction by multiplying each side by 3. Then he multiplied 2 to the items in the paranthesis.
C. I prefer Jon's method. Fractions can be tricky. I prefer to remove them as soon as possible. This time the items in the paranthesis had whole numbers. But had any of them been a fraction too, the problem would have gotten a lot more tricky and it would very easy to make a mistake or miscalculate something.
Answer:

Step-by-step explanation:
Area of a rectangle is simply length times width
{
} * x would be the area
That can be simplified to

Which can be further simplified to

Let x = amount of sales (in dollars)
The salary is $400 and there's an additional 0.06x dollars added on to get to the goal of 790. The equation is therefore
<span>400+0.06x = 790
</span>
Let's solve for x
400+0.06x = 790
<span>400+0.06x-400 = 790-400
</span>0.06x = 390
0.06x/0.06 = 390/0.06
x = 6500
The final answer is 6500
This means he must have $6,500 in sales.