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jeka57 [31]
3 years ago
13

Solve for b. 76 - 15 = 56 - 3 PLEASE HELP

Mathematics
2 answers:
Sav [38]3 years ago
8 0
It’s 53 easy hope this helped
Andre45 [30]3 years ago
6 0

Answer:53

Step-by-step explanation:

Use a calculator lol

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If 160 is divided by x, then the remainder is 4. What is the remainder when 315 is divided by x?
frutty [35]
Let us rewrite this equation as:
<em>160/x = some number + 4/x
</em>we can assume that some number of x's can fit into 160, but x is greater than 4 so we have a remainder.
We can figure out by using the remainder that x is completely divisible into (160-4) or 156. Knowing this we can assume that x is some factor of 156 that is greater than 4. 
Let us list the factors of 156
1,2,3,4,6,12,13,26,39,52,78,156
Now let us refer back to the restrictions we put on x.
<em>x must be > 4 as anything less than 4 would divide at least 1 more time into it. So now we are left with a bunch of other factors. And the cool thing is that all of the factors excluding anything that is = or < 4 all work for getting a remainder of 4. Thus we can use the largest factor and set it equal to x.
</em>So x = 156
then if we divide 315 by x or <em>315/x = 315/156 = 2 and a remainder of 3
so the answer would be 3.</em>
4 0
3 years ago
What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth
uysha [10]

Answer:

The perimeter of the trapezoid is 38.25\ units

Step-by-step explanation:

we know that

The perimeter of the trapezoid is the sum of its four side lengths

so

In this problem

P=QR+RS+ST+QT

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

Q(8, 8), R(14, 16), S(20, 16),T(22, 8)

step 1

Find the distance QR

Q(8, 8), R(14, 16)

substitute the values in the formula

d=\sqrt{(16-8)^{2}+(14-8)^{2}}

d=\sqrt{(8)^{2}+(6)^{2}}

d=\sqrt{100}

QR=10\ units

step 2

Find the distance RS

R(14, 16), S(20, 16)

substitute the values in the formula

d=\sqrt{(16-16)^{2}+(20-14)^{2}}

d=\sqrt{(0)^{2}+(6)^{2}}

d=\sqrt{36}

RS=6\ units

step 3

Find the distance ST

S(20, 16),T(22, 8)

substitute the values in the formula

d=\sqrt{(8-16)^{2}+(22-20)^{2}}

d=\sqrt{(-8)^{2}+(2)^{2}}

d=\sqrt{68}

ST=8.25\ units

step 4

Find the distance QT

Q(8, 8),T(22, 8)

substitute the values in the formula

d=\sqrt{(8-8)^{2}+(22-8)^{2}}

d=\sqrt{(0)^{2}+(14)^{2}}

d=\sqrt{196}

QT=14\ units

step 5

Find the perimeter

P=10+6+8.25+14=38.25\ units

6 0
4 years ago
Read 2 more answers
1.23 x 1.1 equals =
Snowcat [4.5K]

Answer:

1.23 x 1.1 = 1.32

3 0
3 years ago
There are 365 days in a common year how many comman days in 3 common year
kari74 [83]
I guess you just have to multiply 365 x 3. Since there is 365 days in one year, just add it two more times to see how many days in all. So the answer should be 1,095. 
4 0
3 years ago
Read 2 more answers
Each child ticket for a ride costs $3, while each adult ticket costs $5. if the ride collected a total of $115, and 33 tickets w
yaroslaw [1]
There were 8 of the $5 and 25 $3
7 0
2 years ago
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