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skad [1K]
3 years ago
14

Help pls!! .................................

Mathematics
1 answer:
tekilochka [14]3 years ago
5 0

Answer:

Step-by-step explanation:

B   no b/c  7 miles is 12,320 yds and 40 times around route is only 9600 yds... keep running cyrus.. :P  

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A gardener wants to make a rectangular enclosure using a wall as one side and 120 m of fencing for the other three sides. expres
Solnce55 [7]
The area is given by A = -2x<span>² + 120x. The</span> greatest area is given by x = 30 m.

Explanation:
See the picture attached for reference.

Let's call:
x = side not facing the wall
We know that the total fence is 120m, therefore
(120 - 2x) = side facing the wall

Note: you could choose to be x = side facing the wall, but the calculations would be a little bit more complicated.

We can now calculate  the area of a rectangle:
A = b · h =
   = x · (120 - 2x)
   = -2x² + 120x

In order to find a maximum for this function, we need to calculate the first derivative:
\frac{d}{dx} (-2x^{2}  + 120x ) = -4x +120

Then, we need to find the candidate points by setting the derivative equal to zero:
<span>-4x +120 = 0
-4(x - 30) = 0
x = 30

Now, in order to understand if the candidate point is a maximum or a minium, let's calculate the second derivative:

</span><span>\frac{d}{dx}(-4x + 120) = -4</span>

According to the "Second Derivative Test", if the second derivative is negative, the point is a local maximum.

Hence, x = 30m gives the greatest area, and we would have:
side not facing the wall = 30m
side facing the wall = 120 - 2·30 = 60m
area = 30 · 60 = 1800 m² 

3 0
4 years ago
If (ax+2)(bx+7)=15x2+cx+14 for all values of x, and a+b=8, what are the 2 possible values fo c
dolphi86 [110]

Given:

(ax+2)(bx+7)=15x^2+cx+14

And

a+b=8

Required:

To find the two possible values of c.

Explanation:

Consider

\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}

So

\begin{gathered} ab=15-----(1) \\ 7a+2b=c \end{gathered}

And also given

a+b=8---(2)

Now from (1) and (2), we get

\begin{gathered} a+\frac{15}{a}=8 \\  \\ a^2+15=8a \\  \\ a^2-8a+15=0 \end{gathered}a=3,5

Now put a in (1) we get

\begin{gathered} (3)b=15 \\ b=\frac{15}{3} \\ b=5 \\ OR \\ b=\frac{15}{5} \\ b=3 \end{gathered}

We can interpret that either of a or b are equal to 3 or 5.

When a=3 and b=5, we have

\begin{gathered} c=7(3)+2(5) \\ =21+10 \\ =31 \end{gathered}

When a=5 and b=3, we have

\begin{gathered} c=7(5)+2(3) \\ =35+6 \\ =41 \end{gathered}

Final Answer:

The option D is correct.

31 and 41

8 0
1 year ago
PLS HELP ME PLS SOVLE THIS WITH THE LIKE TERMS I ONLY HAVE 25 MINS TO FINISH THIS
Basile [38]

Answer:

Step-by-step explanation:

Here are the 3 answers you needed :)!!!

8 0
3 years ago
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PLEASE HELP I NEED THE ANSWER<br> I WILL MARK BRAINLIEST AND MARK THANKS
Kitty [74]
C!!

i need 20 characters lol
6 0
3 years ago
10 to the power of 5/ 10 to the power of 2​
MArishka [77]

Answer:

10

Step-by-step explanation:

((10)^5/10)^2 = 10^1 = 10

8 0
3 years ago
Read 2 more answers
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