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xxMikexx [17]
4 years ago
5

Gcf of 3y^2,6y^3,10y^4

Mathematics
1 answer:
Stolb23 [73]4 years ago
7 0
The GCF of those three monomials is y². 
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Explain why the equation 6|x| + 25 = 15 has no solution. When one solves, they arrive at a step where |x| is equal to a negative
LekaFEV [45]

Answer:

B

Step-by-step explanation:

Lets start solving until we get stuck,

6|x|+25=15

Subtract 25 from both sides

6|x|+25-25=15-25

Subtract

6|x|=-10

Divide both sides by 6

6|x|/6=-10/6

Divide

|x|=-10/6

We get stuck here, we need x to be negative but we cant have a negative x since we have absolute value. This means the answer is b.

5 0
4 years ago
find the equation of a line that is parallel to the straight line 2x-y=-3 and crosses the x-axis at x=-5​
Alecsey [184]

Answer:

y=2x+10

Step-by-step explanation:

In line equations its helpful to write your line in the form y = ax + b. This helps because a is always the gadient of the line and b is always the y intercept.

In this case it is y=2x+3

All parallel lines have the same gradient. The gradient of this line = 2.

If the line crosses the x axis at x=-5, then when x =-5 y = 0.

If you put all this in the form y =ax + b you get 0 = 2(-5) +b

So all you need to do to find b is rearrange. b = 10.

Therefore your line has gradient 2 and y intercept 10.

y = 2x + 10

7 0
3 years ago
Can someone please help me with this question?
kow [346]
Sine = opposite / hypotenuse
If we think of the hypotenuse =1, then sine(C) = x / 1 or just "x"
The sine (A) = adjacent / hypotenuse = y / 1 or just "y"


4 0
3 years ago
Im confused on how to solve this
andre [41]

Answer:

x=7

Step-by-step explanation:

7x-7=4x+14

3x=21

x=7

8 0
4 years ago
Read 2 more answers
Rackham Graduate School has 8,000 students (5,000 PhD students and 3,000 masters stu- dents). The Rackham Student Government Exe
Free_Kalibri [48]

Answer:

a) 8,000!/(8000 - 4)! ways

b) 15,000,000 + 7998!/(7998 - 2)! ways

c) 5,000 + 7,999!/(7,999- 3)! ways

d) 3,000 + 7,999!/(7,999- 3)! ways

Step-by-step explanation:

The number of students at Rackham Graduate School = 8,000 students

The number of PhD students = 5,000

The number of masters students = 3,000

The number of student members of the Rackham Student Government Executive Board = 4 students

a) The number of ways there are to choose the Exec Board from all Rackham students = The number of ways to choose 4 students from 8,000 = 8,000!/(8000 - 4)!

b) The number of ways of having one Master student in the board = 3,000 ways

The number of ways of having one PhD student in the board after selecting a masters student = 5,000 ways

The number of ways of selecting the remaining 2 members =

7998!/(7998 - 2)!

The total number of ways of selecting at least one masters and one PhD in the board is therefore equal to 5,000 × 3,000 + 7998!/(7998 - 2)! ways

c) The number of ways of choosing the VP position as PhD = 5,000 ways

The number of ways of choosing the other three members = 7,999!/(8000 - 3)!

Therefore, the total number of ways = 5,000 + 7,999!/(7,999- 3)! ways

d) The number of ways of choosing a masters student as the VP position = 3,000 ways

The number of ways of choosing the other three members = 7,999!/(8000 - 3)!

Therefore, the total number of ways = 3,000 + 7,999!/(7,999- 3)! ways

8 0
3 years ago
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