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3 years ago

Convert the following to Standard Form: (x - 5)^2 + 4

Mathematics

1 answer:

netineya [11]3 years ago

5 0

Answer:

x² - 10x + 29

Step-by-step explanation:

The standard form of a quadratic is , ax² + bx + c (a ≠ 0 )

Given

(x - 5)² + 4 ← expand factor using FOIL

= x² - 10x + 25 + 4

= x² - 10x + 29 ← in standard form

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use the elimination method to solve the system of equations. choose the correct ordered pairs -x + y=-3 and 3x + 2y=9

Agata [3.3K]

-x+y=-3, 3x+2y=9

1. multiply the first row by the second
-2x+2y=-6, 3x+2y=9

2. subtract the second row from the first row
-5x=-15

3. sole for x in the above equation
x=-15/-5
x=15/5
x=3

4. substitue x=3 into -2x+2y=-6
-2*3+2y=-6

5. solve for y in the above equation
-6+2y=-6
2y-6=-6
2y=0
y=0

6 therefore,
x=3 and y=0

Have a nice day :D

3 0

3 years ago

There are 9 students in a class: 2 boys and 7 girls. If the teacher picks a group of 4 at random, what is the probability that e

notsponge [240]

Answer:

<h2>28% probability that every student in the group is a girl.</h2>

Step-by-step explanation:

In this problem we have independent events, that is, the event "picking a girl" doesn't affect an "picking a boy", also, picking picking a girl doesn't affect the probability of the other subjects.

So, the probability when the first girl is being picked is:

$P_{1}=\frac{7 \ girls}{9 \ students}$

Because among the total 9 students, there are 7 girls.

Now, after picking one girl, there remains 6 girls and 8 students to be picked. So, the probability of the second girl would be:

$P_{2}=\frac{6 \ girls}{8 \ students}$

Then, the probability of the third girl:

$P_{3}=\frac{5 \ girls}{7 \ students}$

The fourth girl probability:

$P_{3}=\frac{4 \ girls}{6 \ students}$

Therefore, the probability of picking all 4 girls would be the product of each probability, because events are independent (we use product when they are independent):

$P=\frac{7 \ girls}{9 \ students} \times \frac{6 \ girls}{8 \ students} \times \frac{5 \ girls}{7 \ students} \times \frac{4 \ girls}{6 \ students}\\P=\frac{5}{18}=0.28 \ (or \ 28\%)$

Therefore, there's 28% probability that every student in the group is a girl.

5 0

3 years ago

51x+x+33x+10 <br> I need help on combining like terms

Serhud [2]

Answer:

84x+10

Step-by-step explanation:

Ok, since 51x, x, and 33x all have x in it, you add them all together. From that, you should get 84x. We can not add 10 with anything, the expression in simplest form is 84x+10.

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3 years ago

A company that manufactures toothpaste is studying five different package designs. Assuming that one design is just as likely to

Vesna [10]

Answer:

20%

Step-by-step explanation:

p(outcomes)=#of favourable outcomes/#of possible outcomes

=1/5

=0.2

=20%

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3 years ago

What is the answer for the picture.

spin [16.1K]

Answer:

Step-by-step explanation:

40-36=4

6 0

3 years ago

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