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3 years ago

The forces exerted on an object are shown.

Mathematics

2 answers:

Mazyrski [523]3 years ago

5 0

Answer:

The answer is 5n

Step-by-step explanation:

Since the force on the right would have to be greater, and the force on the right is 6n, the left force would have to be less. Therefore, the answer is 5n.

yan [13]3 years ago

3 0

Answer:

So you have a box, with weight Wb and you have a right force of 6N and a left force of Fl

With sum of forces you get that to maintain equilibrium the force Fl must be 6 therfore to maintain moving right the left force must be 5N

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PLEASE HELP 50 points

hoa [83]

Answer:

r > 7 (C)

Step-by-step explanation:

3r−7>14

Step 1: Add 7 to both sides.

3r−7+7>14+7

3r>21

Step 2: Divide both sides by 3.

r>7

Hope this helps and makes sense!! Good luck and have a wonderful day! <33

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Soloha48 [4]

$\underline \mathcal \pink{ GIVEN}$

Base = 2 9/10 km
Height = 4 6/7 km

$\underline \mathcal \purple{ TO \: FIND}$

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$\underline \mathcal \blue{CALCULATION}$

$\qquad \tt \leadsto \: area = \frac{1}{2} \times base \times height$

$\qquad \bf \nrightarrow \: area = \frac{1}{ \cancel2} \times \cancel2 \frac{9}{10} \times 4 \frac{6}{7}$

$\qquad \bf \nrightarrow \: area = \frac{9}{ \cancel{10}} \times \cancel4 \frac{6}{7}$

$\qquad \bf \nrightarrow \: area = \frac{9}{ 5} \times 2 \frac{6}{7}$

$\qquad \bf \nrightarrow \: area = \frac{108}{ 35} \approx3.08 \: {km}^{2}$

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2 years ago

What do we do to both sides of the equation? X-8=3

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Answer:

$\huge\fbox\red{a}\huge\fbox\orange{n} \huge\fbox\pink{s}\huge\fbox\green{w} \huge\fbox\blue{e}\huge\fbox\purple{r}\$

We'll add 8 to the both side of the equation on order to get the Value of x
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