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2 years ago

(-1, 4) and (0,-1) writing out linear equations giving two points

Mathematics

1 answer:

Viefleur [7K]2 years ago

8 0

Answer:

The equation is y = -5x - 1.

Step-by-step explanation:

1. Find the slope using the formula. Slope = (4 + 1) / (-1 - 0) which is equal to 5 / -1 which is -5.

2. Use the slope-point formula to construct an equation. The equation is y - 4 = -5 * (x + 1)

3. Simplify. We would get y = -5x - 5 + 4, which is y = -5x - 1.

Answer: The equation is y = -5x - 1.

You might be interested in

Find the product of 51 and -2.5.

yaroslaw [1]

The answer is C because 51×-2=-102 and 51×-0.5=-25.5

So it -102+(-25.5) or C

6 0

3 years ago

Read 2 more answers

The system of equations may have a unique solution, an infinite number of solutions, or no solution. Use matrices to find the ge

Leno4ka [110]

Answer:

Infinite number of solutions.

Step-by-step explanation:

We are given system of equations

$5x+4y+5z=-1$

$x+y+2z=1$

$2x+y-z=-3$

Firs we find determinant of system of equations

Let a matrix A= $\left[\begin{array}{ccc}5&4&5\\1&1&2\\2&1&-1\end{array}\right]$ and B= $\left[\begin{array}{ccc}-1\\1\\-3\end{array}\right]$

$\mid A\mid=\begin{vmatrix}5&4&5\\1&1&2\\2&1&-1\end{vmatrix}$

$\mid A\mid=5(-1-2)-4(-1-4)+5(1-2)=-15+20-5=0$

Determinant of given system of equation is zero therefore, the general solution of system of equation is many solution or no solution.

We are finding rank of matrix

Apply $R_1\rightarrow R_1-4R_2$ and $R_3\rightarrow R_3-2R_2$

$\left[\begin{array}{ccc}1&0&1\\1&1&2\\0&-1&-3\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\1\\-5\end{array}\right]$

Apply $R_2\rightarrow R_2-R_1$

$\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&-1&-3\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\6\\-5\end{array}\right]$

Apply $R_3\rightarrow R_3+R_2$

$\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&0&-2\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\6\\1\end{array}\right]$

Apply $R_3\rightarrow- \frac{1}{2}$ and $R_2\rightarrow R_2-R_3$

$\left[\begin{array}{ccc}1&0&1\\0&1&0\\0&0&1\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]$

Apply $R_1\rightarrow R_1-R_3$

$\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]$ : $\left[\begin{array}{ccc}-\frac{9}{2}\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]$

Rank of matrix A and B are equal.Therefore, matrix A has infinite number of solutions.

Therefore, rank of matrix is equal to rank of B.

4 0

3 years ago

What does x= in the equation?

vampirchik [111]

Answer:

3.5

Step-by-step explanation:

2x + 5 = 12

-- minues five from both sides --

2x = 7

-- divide both sides by two ---

x = 3.5

<em><u>Please give brainliest. </u></em>

4 0

3 years ago

What is the relationship between a rotation and a reflection? Sketch a diagram that supports your explanation.

SSSSS [86.1K]

Answer with Step-by-step explanation:

Relationship between rotation and reflection:

In reflection, the pre-image gets flips across the same line.

whereas in rotation, the pre-image get spin around a point.

Rotations can be represented as two reflections i.e. the composition of reflections over two intersecting lines is always equal to rotation of that object.

In rotation, the object will get turned, this is turning some degree either clockwise or anti-clockwise.

Hence, rotation requires spinning and reflection requires flipping.

6 0

3 years ago

A state offers two lottery games, WinOne and PlayBall. Both games cost $2 per ticket.

uysha [10]

In this question, both tickets cost 2$ per ticket.
The answer to this question would be: $0

In WinOne scenario, you need to match a ticket that has to pick from A-J(10 possibilities) and 0-9 (10 possibilities). The chance to win would be: 1/10* 1/10= 1/100

The expected value must be:
E= chance to win * win amount - ticket price
E= 1//100*$200 - $2= $2-$2= 0

8 0

2 years ago

(-1, 4) and (0,-1) writing out linear equations￼ giving two points

(-1, 4) and (0,-1) writing out linear equations giving two points