How many gallons per day is 32 ounces per day?

Mathematics

1 answer:

natali 33 [55]3 years ago

4 0

Answer: 4096

Step-by-step explanation: 1 gallon=128 ounces, 128x32=4096

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Bobby's dad is 41 and is 6 more than 5 times Bobby's age. Bobby's little sister Emma is one less than half his age. How old are

34kurt

Bobby is 7 and his sister is 3.

Explanation : his dads age : 41
since his dads age is six more than, you would subtract 6 from 41 to get 35.
and since 35 is 5 times bobby’s age you would divide 35 by 5 to get 7
So bobby is 7.

bobby’s sister :
bobby’s age : 7
bobby’s little sisters age is one less than half of his age you subtract 1 from 7 and you would get 6
Now that it’s one less you have to find half so divide 6 by 2 and you’ll get 3
So bobby’s sister is 3.

bobby’s age : 41 - 6 = 35
35 (divided by) 5 = 7
bobby’s sister : 7 - 1 = 6
6 (divided by) 2 = 3

8 0

3 years ago

I need help please!!!

Nuetrik [128]

If I'm looking at it right I believe it would be 2 inches... If that wasn't right I'm really sorry.

4 0

3 years ago

Read 2 more answers

Pls help! I'm confused. Can you explain this if you can.

alexdok [17]

Answer:

From a table, for an ordered pair (0, y), y will not be zero. From a graph, the y-intercept will not be zero. From an equation, it will have the form, y = mx + b where b is ≠ 0.

Step-by-step explanation:

From a table, for an ordered pair (0, y), y will not be zero. If there is not a constant rate of change in the data displayed in a table, then the table represents a nonlinear nonproportional relationship.
From a graph, the y-intercept will not be zero. This means that it doesn't contain or go through the origin.
From an equation, it will have the form, y = mx + b where b is ≠ 0. (not equal to zero). If an equation is not a linear equation, it represents a nonproportional relationship. A linear equation of the form y = mx + b may represent either a proportional (b = 0) or nonproportional (b ≠ 0) relationship. Therefore, when b ≠ 0, the relationship between x and y is nonproportional.

7 0

3 years ago

A second particle, Q, also moves along the x-axis so that its velocity for 0 £ £t 4 is given by Q t cos 0.063 ( ) t 2 v t( ) = 4

Vladimir79 [104]

Answer:

The time interval when $V_Q(t) \geq 60$ is at $1.866 \leq t \leq 3.519$

The distance is 106.109 m

Step-by-step explanation:

The velocity of the second particle Q moving along the x-axis is :

$V_{Q}(t)=45\sqrt{t} cos(0.063 \ t^2)$

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.

We are also to that :

$V_Q(t) \geq 60$ between $0 \leq t \leq 4$

The schematic free body graphical representation of the above illustration was attached in the file below and the point when $V_Q(t) \geq 60$ is at 4 is obtained in the parabolic curve.

So, $V_Q(t) \geq 60$ is at $1.866 \leq t \leq 3.519$

Taking the integral of the time interval in order to determine the distance; we have:

distance = $\int\limits^{3.519}_{1.866} {V_Q(t)} \, dt$